more math for math-capable people?

Question

well my last question had an error in it but i still got what i needed. this next problem is a different sort so i need help with it too. try your hand at: 5kx-x=25k{squared}-10k+1.if you wish you can figure out the other problem, corrected: abx-b=ax-1. thanks. i am a National Spelling Bee participant and will gladly help with grammar. just not math.

Answer 1

Sorry, but I have to point out the irony that you would "help with grammar" and yet you typed that? Commas? Capitalization? Fragmentation? :)

Also,
5kx-x=25k^2-10k+1 <-given
x(5k-1)=25k^2-10k+1 <-factor out x
x(5k-1)=(5k-1)(5k-1) <-factor right side
x=5k-1 <- good ol' division

Answer 2

5kx - x = 25^2 - 10k + 1

x(5k - 1) = (5k - 1)^2

x= 5k - 1
[if k does not equal 1/5, which has been very conveniently not mentioned]

abx - b = ax - 1
abx - ax = b - 1
ax(b - 1) = b - 1
x = 1/a (if b does not equal 1 , which has been very conveniently not mentioned again, wherever ur from, math there is pathetic)



And this is math for morons and not math-capable people

Answer 3

qn is 5kx - x = 25 k^2 - 10k + 1
thus, x(5k-1) = (5k-1)(5k-1) factoring the left side and right side separately
thus, x = 5k-1

2qn abx - b = ax - 1
thus, abx - ax = b -1 taking b from left to right and bringing ax from right to left
thus, ax (b - 1) = (b - 1) taking ax common from the left side
thus, ax = 1
thus, x = 1/a

Answer 4

5kx-x=25k^2-10k+1
x(5k-1)=25k^2-10k+1
x(5k-1)=(5k-1)(5k-1)

If k is not equal to 1/5, we can divide both sides by 5k-1. (If k=1/5, 5k-1=0 and division by zero is not allowed)

Hence,

x=5k-1

Answer 5

if u tell me what ur previous question was or what u want to find in this problem, i may be able to solve it.