a = 2, b = 1, c = 7, d = 8
2178 * 4 = 8712
Damn, woman beat me to it, but that's how I did it.
2006-07-25 15:30:52
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answer #1
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answered by sgp19 2
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First of all, A cannot be greater than 2, because 4 x 3 = 12, and
we would have another digit to the left of the D in the product.
A cannot be 0, because we don't write numbers with a 0 on the left.
And A cannot be 1, because 4 times anything is even, so we can't get
a 1 as the last digit of the product. So A must be 2, and we have
2BCD
4
----
DCB2
Now looking at the leftmost digit of the product, we see that D must
be 8 or 9, and it can't be 9, because 4 X 9 is 36, and we wouldn't get
the 2 in the product. So we have
2BC8
4
----
8CB2
Now since there's no carry into the leftmost position of the product
(otherwise we would have a 9 and not an 8), B must be 0, 1, or 2, and
it's not 2, because we've already used 2. It's not 0 either, but I'm
going to let you figure out why. Assuming you've figured that out, we
have to have B = 1, and you should be able to finish it off from
there. (There are only a few possibilities at this point).
2006-07-25 22:27:31
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answer #2
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answered by woman38 5
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If it is an algebra question and abcd does not represent a number. abcd has to equal zero.
in algebra abcd must equal dcba. Numbers multiplied together order doesn't matter. The only number that would work for the equation is zero.
2006-07-25 23:24:10
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answer #3
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answered by ? 6
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4 x abcd
2006-07-25 22:25:53
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answer #4
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answered by BK4EvEr 2
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abcd=dcba/4
2006-07-25 22:24:51
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answer #5
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answered by jen12121980 3
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a=2
b=1
c=7
d=8
therefore abcd*4=2178*4=dcba=8712
VERIFY IT
2006-07-25 22:36:23
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answer #6
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answered by Gaurab N 3
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