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Sweet Home Alabama is a song by Southern rock band Lynyrd Skynyrd, which first appeared in 1974 on their second album, Second Helping.
2)
"Born to Be Wild" is a song by the band Steppenwolf, initially released in 1968, but subsequently released on many different collections, the first one being the film Easy Rider. It is often used in popular culture to denote a biker appearance or mentality, and is frequently regarded as the first 'heavy metal' song ever written.
2006-07-25 15:20:01
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answer #1
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answered by QB 1
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Sweet Home Alabama = Lynard Skynard
Born To Be Wild = Steppenwolf
2006-07-25 15:21:10
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answer #2
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answered by sf_brat94114 1
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Sweet Home Alabama = Lynyrd Skynyrd (around 1977)
Born To Be Wild = Steppenwolf (around 1969)
2006-07-25 15:21:33
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answer #3
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answered by Mr. Scandalous 4
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Sweet Home Alabama is by Lynyrd Skynyrd. And Born to be Wild is by Steppenwolf.
2006-07-25 15:24:21
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answer #4
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answered by rebekkah hot as the sun 7
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Sweet Home Alabama is Lynyrd Skynyrd, and Born to be Wild is Steppenwolf.
2006-07-25 15:21:58
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answer #5
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answered by flyingbumblebee 5
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Sweet Home Alabama is by Lynyrd Skynyrd and Born to be Wild is by Steppenwolf. Great songs!!!!!
2006-07-25 15:36:29
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answer #6
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answered by toughguy2 7
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Lynard Skynard plays Sweet Home Alabama dont' know about born to be wild
2006-07-25 15:21:11
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answer #7
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answered by Anonymous
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Sweet Home Alabama is sung by Lynyrd Skynyrd
and Born to be Wild is sung by Steppenwolf. hope this helps
2006-07-25 15:21:28
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answer #8
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answered by confused 2
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sweet home alabama -Lynord Skynard
BORN TO BE WILD. From the 1968 release "Steppenwolf"
2006-07-25 15:21:53
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answer #9
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answered by woman38 5
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SWEET HOME Alabama is sung by Lynyard Skynyrd
Born to be wild is sung by Steppenwolf
2006-07-25 15:25:42
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answer #10
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answered by smile24_8 2
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