you would need 109..
working:
you need totally 93 X 4 = 372
you have already got 80 + 88 + 95 = 263
so the remaining is 109
i like your determination to do well.. it's ok even if you did not succeed.. better luck next time..
2006-07-25 15:15:30
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answer #1
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answered by yrzfuly 3
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Four tests average out to a 93 test average
=( 80 + 88 + 95 + x) / 4 = 93
4 * 93 = 80 + 88 + 95 + x
372 = 263 + x
x = 109
Approach your teacher and ask what you can do at this point to get an "A" in the class.
2006-07-25 16:16:50
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answer #2
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answered by Anonymous
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You will have a 93% average score on 4 tests if your tests add up to 372 (since 372 is 93% of 400 and 400 is the most possible).
Your current total is 80+88+95 =263
To reach 372 you would need 109 on the last test. 263+109 = 372
So it isn't possible to obtain a 93% average.
2006-07-25 15:17:23
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answer #3
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answered by Demiurge42 7
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your first test = 80
your second = 88
your third = 95
your fourth = x
average = (80 + 88 + 95 + x) / 4 = (263 + x) / 4 = 93
x = (93 x 4) - 263 = 109
i have no idea how you're gonna get 109/100 for your test. lol.
the maximum average you can get is if you scored full marks for your 4th test:
(80 + 88 + 95 + 100)/4 = 363/4 = 90.75%
2006-07-25 17:15:28
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answer #4
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answered by Anonymous
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You would need to get 109.
80 + 88 + 95 +109 = 372
372 divided by 4 is 93
2006-07-25 15:19:28
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answer #5
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answered by momma2more 3
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93 = (80 + 88 + 95 + x) / 4
372 = 263 + x
109 = x
Hope you can earn extra credit, pal, because you need a 109% on that last test.
2006-07-25 17:10:06
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answer #6
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answered by jimbob 6
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80+85+95+100+EXTRA CREDIT/4=.93
2006-07-25 15:19:53
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answer #7
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answered by Anonymous
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(.80+.88+.95+x)/4 = .93
Solve for x
2006-07-25 15:12:14
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answer #8
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answered by Anonymous
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((80 + 88 + 95 + x)/4) = 93
263 + x = 372
x = 109
so it isn't possible unless you have extra credit
2006-07-25 15:47:42
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answer #9
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answered by Sherman81 6
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You could not get a 93%. The 80% lowers the average too far, the most you could get would be 90.7%
2006-07-25 15:14:55
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answer #10
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answered by lunagoddess777 1
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