Hadleytown has a present population of 100,000 and the population increases by 3% each year. What will the population be in 15 years? How long will it take for the population to double?
2006-07-25 14:28:29 · 8 answers · asked by Enrique P 1 in Science & Mathematics ➔ Mathematics
P=100,000 * 1.03^t
P_15 = 100,000 * 1.03^15
2 = 100,000 * 1.03^x
1/50,000 = 1.03^x
log(1/50,000)/log(1.03) = x
2006-07-25 14:34:22 · answer #1 · answered by Charles G 4 · 0⤊ 1⤋
If you don't need an exact answer for questions like these, use the rule of 72: a given amount n will increase to 2n in approximately 72/p years, with p = percent rate of increase.
In this case, the population will double roughly every 24 years.
2006-07-26 00:15:41 · answer #2 · answered by jimbob 6 · 0⤊ 0⤋
In 15 years the population of Hadleytown would be 155796 (rounded off).
In 24 years the population will be double.
This can be done through compound interest formula also.
2006-07-25 22:24:35 · answer #3 · answered by yrzfuly 3 · 0⤊ 0⤋
122,987 people in 15 years doubling in 24
2006-07-25 21:33:33 · answer #4 · answered by Alexander R 3 · 0⤊ 0⤋
Another Homework question
2006-07-25 21:54:31 · answer #5 · answered by st_creations2003 2 · 0⤊ 0⤋
15 years = 145,000
33 years = 202,000
2006-07-25 21:39:39 · answer #6 · answered by Anonymous · 0⤊ 0⤋
P = 100000(1.03)^t
P = 100000(1.03)^15
P = about 155797 people
200000 = 100000(1.03)^t
2 = (1.03)^t
t = log(1.03)2
t = (log2)/(log(1.03))
t = 23.4497722
Time : about 23 or about 23.45 years
2006-07-25 21:57:55 · answer #7 · answered by Sherman81 6 · 0⤊ 0⤋
100000(1.03)^15
then substitute. 200,000= 100000(1.03)^t
solve for t
2=(1.03)^t
logbase2?logbase1.03= t
2006-07-25 21:33:03 · answer #8 · answered by swiftassailant77 2 · 0⤊ 0⤋