This is how the question is asked?

Question

Add ! 3 / x + 4 + 6 / x^2 + 2x I dont't think that I'm supposed to solve for X, I think it is just redused to lowest terms

Answer 1

you need to clarify your question with some parenthesis. you may be able to simplify it a little

Answer 2

I assume that the question is: Simplify 3/(x+4) + 6/(x^2+2x). If the brackets are not there then the question is pointless. Assuming the brackets are in the indicated positions then the common denominator is x(x+2)(x+4) and the numerator will be 3(x^2+2x)+6(x+4) = 3(x^2+4x+8) which does simplify further. Thus the simplified form is

3(x^2+4x+8)/[x(x+2)(x+4)]

Answer 3

If that is the question, then it is already simplified.

Edit: If it is 3/[x+4] + 6/[x^2 +2x], then you add fractions with LCD which is 2x(x+2). You need to use the brackets to symbolize the fact that there is more than one term in the denominator. This type of problem would be "writing as one term (or perform the indicated operation) and simplify" not just simplifying.

Answer 4

First, make them all into fractions (3/x)+(4/1)+(6/x^2)+(2x/1)
Second, make them all have the same denominator by multiplying (3/x) by (x/x) and (4/1)&(2x/1) by (x^2/x^2) you will leave (6/x^2) alone
You'll end up with this: (3x^2/x^2)+(4x^2/x^2)+(6/x^2)+(2x^3/x^2)
You can then just pay attention to the top and add.
Your final answer will be (2x^3+4x^2+3x+6)/x^2

Answer 5

indeed you can not solve for x because ther is no (in)equality witten.

I think that you need to write all the terms together as a quotient.

3/x + 4 = 3/x + 4x/4 = (3+4x) / 4

this you have to do for : 3 / x + 4 + 6 / x^2 + 2x

Answer 6

3/x+4/1+6/x^2+2x/1
=(3x+4x^2+6+2x^3)/x^2
=(2x^3+4x^2+3x+6)/x^2