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I want to know exactly what species are present in an acid base titration, EXACTLY at the equivlance point.

Throw a little "why" in there and I will give you best answer. THanks

2006-07-25 13:33:15 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

Oh yes, and in what relative amounts are they present? Assume the acid is diprotic, therefore there are two equiv points. H2A is the acid.

2006-07-25 13:34:57 · update #1

4 answers

What's your base?
At the equivalence point all of the acid will have reacted with the base. For a diprotic acid you have two equivalence points:the first equivalence point will be when all of the H(+) from one group of the acid have reacted.
Assuming a strong monovalent base BOH and that the acid is weak

BOH + H2A -> B(+) + HA(-) + H2O but also
HA(-) <=> H(+) + A(-2)
and HA(-) + H2O <=> H2A +OH(-)

So your species at the first equivalence point are B(+), HA(-), H(+), A(-2) and H2A

At the second equivalence point

BOH + HA(-) -> B(+) + A(-2) + H2O but also
A(-2) + H2O <=> HA(-) + OH(-)
HA(-) + H2O <=> H2A + OH(-)

So the species will be B(+), A(-2), HA(-), OH(-) and H2A

Actually H(+) (and OH(-)) will always be present since
H2O <=> H(+) + OH(-) but the amount will be [H+]=Kw/[OH-].

So in effect you always have the same species present but what changes is their concentration. E.g. for the second equivalence point you should have only traces of H2A but since it is an equlibrium you can't have absolutely zero.

2006-07-25 22:34:09 · answer #1 · answered by bellerophon 6 · 2 1

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2016-12-14 13:56:31 · answer #2 · answered by ? 4 · 0 0

At an equivalence point there is exactly one specie... So the first equivalence point there is only H2A; the next one only HA-, and finally only A2- at the third. This is because it takes one molar equivalent of strong base to move from one equivalence point to the next (H2A to HA-).

2006-07-25 13:51:11 · answer #3 · answered by kbarnus 2 · 0 0

the answer depends on what your reactants are and how much you have and at what conditions. you have not given enough information to answer your question.

2006-07-25 13:47:48 · answer #4 · answered by Anonymous · 0 0

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