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The question I'm asking is how do you answer this question

3 / 2x + 4 + 6 / x^2 + 2x

2006-07-25 13:13:44 · 11 answers · asked by michael b 1 in Science & Mathematics Mathematics

11 answers

this problem is WHACK

it is easy to solve, but you need to make it more clear what the exact problem is by using parenthesis-for example, is the first term (3/2)x or is it 3/(2x)?

2006-07-25 13:15:33 · answer #1 · answered by Anonymous · 3 1

Do you mean: Solve 3/(2x+4) + 6/(x^2 + 2x) = 0?

If it is then you need to factor the denominators, multiply both sides by the LCD which is 2x(x+2), and then the fractions clear and you have that x = -4.

2006-07-25 13:20:40 · answer #2 · answered by raz 5 · 0 0

i will reduce the eqn first for simplification purpose

since 2x^2 is the least common multiple of the denominators in the qn asked..

multiply the eqn by 2x^2
thus, we get, 3x + 8x^2 + 12 + 8x^3
rearranged, 8x^3 + 8x^2 + 3x + 12

now, this has to be solved for x

you wil get three values of x which when substituted in the above rearranged eqn would give 0

2006-07-25 15:54:25 · answer #3 · answered by yrzfuly 3 · 0 0

This isn't a question! If you had an = somewhere then you could solve for x. However, what you have is just an expression!

2006-07-25 13:16:45 · answer #4 · answered by Aaron 3 · 0 0

what's the ^ mean? I did bad in algebra, and i don't think i ever learned the ^ unless i forgot

Oh yeah i do know you have to change its form to make it an equation first. but no clue how

2006-07-25 13:17:08 · answer #5 · answered by Pat 4 · 0 0

He's right. It's not a problem if there's no =
It's a row of numbers and symbols.

2006-07-25 13:19:44 · answer #6 · answered by Anonymous · 0 0

Buy a TI-69.

2006-07-25 13:16:06 · answer #7 · answered by Johnny P 4 · 0 0

you equal it to 0 and then solve for x

2006-07-25 13:16:12 · answer #8 · answered by MJ 3 · 0 0

You don't.

You can't solve a mathematical expression.

2006-07-25 13:16:14 · answer #9 · answered by OMG! PANCAKES LOLz! 2 · 0 0

who cares

2006-07-25 13:19:53 · answer #10 · answered by mayri 4 · 0 0

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