First factor out a common b from the left side:
b(ax-1) = ab-1
Now divide both sides by b:
ax - 1 = a - 1/b
Next add 1 to both sides:
ax = a - 1/b + 1
Now divide both sides by a:
x = 1 - 1/ab + 1/a
If you want of fix the fraction on the right, notice that you can use a common denominator of ab:
x = ab/ab - 1/ab + b/ab
Now group the numerator:
x = (ab - 1 + b)/ab
An alternate way to do this would be:
abx - b = ab - 1
Add b to both sides:
abx = ab - 1 + b
Divide by ab:
x = (ab - 1 + b)/ab
Same result and even quicker...
Either of these answers should be acceptable.
2006-07-25 12:33:59
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answer #1
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answered by Puzzling 7
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Solve,
abx - b = ab - 1
Rearranging,
abx = ab + b - 1
x = (ab + b - 1)/ab
x = 1 + (b - 1)/ab
2006-07-25 20:30:07
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answer #2
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answered by ideaquest 7
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abx - b = ab - 1
You want to end up with an equation with just
x =
on one side.
You can eliminate the 2nd term on the left side by adding b to that side and, in order to keep things in balance, you must add b to the other side as well.
abx - b + b = ab + b - 1
or
abx = ab + b - 1
You can eliminate the ab in abx by dividing by ab, remembering to do the same on the other side as well.
abx/ab = (ab + b - 1)/ab
x = (ab + b - 1)/ab
We had to introduce parentheses on the right side because we are dividing the entire right side by ab.
2006-07-25 19:47:14
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answer #3
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answered by kindricko 7
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To solve
abx-b=ab-1
first take out the common factor of b on RHS:
b(ax-1) = ab-1
now divide both sides by b:
ax-1 =(ab-1)/b
now add one to both sides:
ax = ((ab-1)/b) + 1
now divide both sides by a:
x = (((ab-1)/b) + 1)/a
yuk! Are you sure you copied the equation correctly?
2006-07-25 19:37:45
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answer #4
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answered by Auriga 5
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Given:
abx-b = ab - 1 (Add b to both sides).
abx = ab - 1+ b (Divide by sides by ab).
x = (ab-1+b) / ab (Divide all parts by ab).
x = ab/ab - 1/ab + b/ab
x = 1 - (1+b) / ab
2006-07-25 19:45:12
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answer #5
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answered by Brenmore 5
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abx-b=ab-1 that implies abx=ab-1+b
that implies x=(ab-1+b)/ab
2006-07-25 21:04:08
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answer #6
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answered by Anonymous
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abx - b=ab - 1
b(ax - 1) = ab - 1
ax - 1 = (ab - 1)/b
ax = a - 1/b + b/b
x = (a - 1/b + 1) / (a)
2006-07-25 19:36:28
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answer #7
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answered by YEAH!!!!! 2
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abx-b=ab-1
abx=ab+b-1
x=(ab+b-1)/ab
x=1+a-(1/ab)
2006-07-25 20:47:07
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answer #8
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answered by J 4
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Exactly as explained above... "Solving" for a variable means you want just that variable on one side of the equal sign and everything else on the other...
2006-07-25 19:37:06
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answer #9
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answered by Chris 2
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