Need Employment answer this 1?

Question

If you hired a person to work for you for 1 month 30 day's to be exact. And paid that person 1 penny per day and doubled the amount every day. How much money will you be paying that person at the end of the month? Example first day 1 penny 2nd day 2 pennies 3rd day 4 pennies and so on...

Answer 1

At the and of the 30th day you would be paying

2^29 = 536870912 pennies, that is $5 368 709.12.

The total pay in that month is double this amount minus 1 penny,

$10 737 418.23

Nice monthly pay!

Answer 2

That would depend on the length of the first month. One month and 30 days.... OH! OOOOH! You mean One Month OR 30 Days! Ok, now I got it.

:)

Well:

day 01 = 1 penny
day 02 = 2 penny
day 03 = 4 penny
day 04 = 8 penny
day 05 = 16 penny
day 06 = 32 penny
day 07 = 64 penny
day 08 = 128 penny
day 09 = 256 penny
day 10 = 512
day 20 = 524,288

notice anything?????

It's 2 to the power of one minus days (or 2 ^ (days - 1))

Therefore, it's 2 ^ 29

or...

536,870,912 pennies, or $5,368,709.12

Answer 3

The answer is 2^(n-1) where n is the number of days employed.
On day 1 this is 2^(1-1) = 2^0 = 1
On day 2 this is 2^(2-1) = 2^1 = 2
On day 3 this is 2^(3-1) = 2^2 = 4
so on day 30 this would be 2^(30-1) = 2^29 = 536870912 pennies
or $5,368,709.12

Answer 4

The total amount of cash you will have paid at the end of 30 days is $10,737,418.23 exactly. The amount paid on the last day is $5,368,709.12 exactly. And this is why you should be wary of anyone who asks you to pay them an exponential amount of cash.

Answer 5

This is a geometric sequence. (1,2,4,8,.....) with 30 terms. Use the sum formula, which is G_1 (1-r^n) divided by 1-r. So,
1(1-2^30)
-------------
-1, which is
1073741823 cents, or $10737418.23