1.)
√12y^5 - √18y -√300y^5 + √98y
2.)
6√15x + 3√15x
2006-07-25 08:49:58 · 4 answers · asked by Brandon ツ 3 in Science & Mathematics ➔ Mathematics
√12y^5 - √18y -√300y^5 + √98y
=2sqrt(3)y^5-10sqrt(3)y^5-3sqrt(2)y+7sqrt(2)y
=-8sqrt(3)y^5+4sqrt(2)y
6√15x + 3√15x
=9sqrt(15)x
2006-07-25 08:54:46 · answer #1 · answered by ag_iitkgp 7 · 2⤊ 1⤋
Ya, I'm 13, I only finished Gr 7... Dont expect me to answer that
2006-07-25 17:31:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1.)
sqrt(12y^5) - sqrt(18y) - sqrt(300y^5) + sqrt(98y)
sqrt((4y^4) * 3y) - sqrt(9 * 2y) - sqrt((100y^4) * 3y) + sqrt(49 * 2y)
(2y^2)sqrt(3y) - 3sqrt(2y) - (10y^2)sqrt(3y) + 7sqrt(2y)
(2y^2 - 10y^2)sqrt(3y) + (-3 + 7)sqrt(2y)
(-8y^2)sqrt(3y) + 4sqrt(2y)
ANS : (-8y^2)sqrt(3y) + 4sqrt(2y) or -4((2y^2)sqrt(3y) - sqrt(2y))
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2.)
6sqrt(15x) + 3sqrt(15x)
(6 + 3)sqrt(15x)
9sqrt(15x)
2006-07-25 22:36:49 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
trying to do your homework last minute
2006-07-25 15:59:09 · answer #4 · answered by kilkubli 1 · 0⤊ 0⤋