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I have 200 Vertices (X,Y) with the step of 1.8 Degree Rotation. In Which Y remains same in all 200 Vertices. Now my problem is How can I Plot them in 3D. (I mean How to find (X,Y,Z))

2006-07-24 19:13:07 · 3 answers · asked by denish c 1 in Computers & Internet Programming & Design

3 answers

Convert as a matrix of (x,y,z) and connect the points in order and u get a drawing to plot

2006-07-24 20:19:27 · answer #1 · answered by karthick k 2 · 0 0

If ax + by using + cz + d = 0 is your director plan and (p,qr) is your concentration then the equation of your paraboloid is ( ax + by using + cz + d )^2 = (a^2 + b^2 + c^2)((x-p)^2 + (y-q)^2 + (z-r)^2) you may anticipate a^2 + b^2 + c^2 = a million. then you have 6 self reliant parameters. so which you would be wanting precisely 6 factors. despite if no longer all families of 6 factors will artwork: working example in case you're taking the vertices of a tetrahedron and a pair of things interior, then no paraboloid will contain those 6 factors. edit "How would my answer substitute if I chosen to have it based far off from the beginning place?" You under no circumstances stated something on the subject count of this in the previous so how do you anticipate the answer to alter? as nicely a paraboloid has no center.

2016-12-10 15:06:42 · answer #2 · answered by donenfeld 4 · 0 0

You should use the IDirect3DRMMeshBuilder-Object to get the the
information of a 3D-Frame or build a 3D Scene.First you have to get the
3D-Frame into the MeshBuilder.
You can do this with: IDirect3DRMMeshBuilder::AddFrame
Now you can get all information you need. For the vertices for exmple
you can call the IDirect3DRMMeshBuilder::GetVertices method.
To convert a MeshBuilder back into a frame use the
IDirect3DRMFrame::AddVisual method.

2006-07-24 23:40:34 · answer #3 · answered by Joe_Young 6 · 0 0

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