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2006-07-24 16:41:22 · 15 answers · asked by Mandykins A 1 in Education & Reference Homework Help

15 answers

2x = y -10
x = ( y - 10 ) /2

2006-07-25 01:01:31 · answer #1 · answered by Massiha 6 · 1 2

Solving fo x

Y = 2x + 10

Y = 2x + 10
-10 - 10

Subtract 10 from both sides

y -10 = 2x

y - 10/2 = 2x/2

Divide both sides by 2

y - 10/2 = x

The answer is x = y - 10/2

2006-07-25 06:53:11 · answer #2 · answered by SAMUEL D 7 · 0 0

is it a graph? of it is then y=mx+c
then compare with the question the intercept y=0
therefore: 0 = 2x+10
-10=2x
-10/2=x
-5=x

2006-07-25 10:42:49 · answer #3 · answered by revelc 3 · 0 0

You gotta be serious. Anyway.
y=2x+10. Subtracting 10 on both the sides.
y-10 = 2x+10-10
y-10=2x.
Dividing both sides by 2.
(y-10)/2=2x/2
(y-10)/2=x.
Solving for x
x=(y-10)/2

2006-07-25 06:21:56 · answer #4 · answered by Bogus Genius 2 · 0 0

When you solve for x in this type of an equation. It's like wrapping/unwrapping a present. (When you unwrap a present you do everything in reverse order of how it was originally wrapped).
The way it is now, first you would multiply the number by 2 and then add 10. To solve for x, you do the opposite.
The last thing you did was add 10. The opposite of adding 10 is subtracting 10. The first thing you did was multiply by 2; the opposite of multiplying by 2 is dividing by 2.
So you subtract 10 and then divide by 2.
Answer: x = (y-10)/2

2006-07-25 01:10:27 · answer #5 · answered by MsMath 7 · 0 0

We need to isolate X on one side of the equation for the answer.

y=2x+10
y-10 = 2x +10 - 10
y-10 = 2x

(y-10)/2 = 2x / 2

(y-10)/2 = x

x = y-10 divided by 2

y-10
-----
2

2006-07-24 23:44:39 · answer #6 · answered by Peter B 4 · 0 0

y=2x+10
y-10=2x
(y-10)/2=x

2006-07-24 23:44:36 · answer #7 · answered by fcas80 7 · 0 0

y=2x+10
-2 -2
y=8

2006-07-24 23:52:04 · answer #8 · answered by Anonymous · 0 0

y=2x+10
-10+y=2x
x= y-10 divided by 2

2006-07-25 06:54:03 · answer #9 · answered by Ananth P 3 · 0 0

(y-10)/2

2006-07-24 23:46:02 · answer #10 · answered by Anonymous · 0 0

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