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I'm stumped on these, I've been able to do some, but the exponent on the outside of the square root is really throwing me off, any help is greatly appriciated. I hope it's readable, typing it out online is rough :), I've included answers for the ones that I was able to work through, although not all of them are complete.

√ = Square Root
^ = Exponent
/ = Numerator/Demoninator

Simplify. Assume that variables can represent any real number.

1) ^3√-8 / x^12
A) -2 / x^3

2) ^5√x^7y^2

3) √25x^6 / 16y^2
A) 5x^3 / 4y

4) (^3√6x)(^3√2y)
A) 2√x/

5) ^5√x^6y^4 / ^5√x^2y^3

6) (^4√xy^2)(√xy)

7) ^5√a^3 / ^4√a^2

8) 7√2 - 3√2
A) 4√2

9) (3 + √x)(7 - 5√x)

10) (√-4)(√-81)
A) 18

11) √48
A) √4√8

12) √36a^2
A) 6a

13) √x^2 - 12x + 36
A) | x - 6 |

14) Rewrite using radical notation: (2ab)^4/5
A) (^5√2ab)^4

15) Rewrite using exponential notation: √6x^2y

16) f(x) = √12 - 3x, determine the domain of f.

17) f(x) = x^2, find f(2 + √6)

18) Rationalize the denominator: √6 / 5 - √5

2006-07-24 15:56:27 · 4 answers · asked by Kevin B 1 in Science & Mathematics Mathematics

4 answers

1) ^3√-8 / x^12

I write this as
(-8/x^12)^3 = (-8)^3 * (1 / x^12 ) ^ 3

next i use this

1/x^n = x^(-n)
(x^p) ^ n = x^(p*n)
^p√ x = x^(1/p)

that is all..

1) ^3√-8 / x^12
A) -2 / x^3 <== is wrong correct==> -2 / x^(12/3)

2006-07-24 21:38:33 · answer #1 · answered by gjmb1960 7 · 1 2

ok, right here is going no longer something: area a million: a million. 3sqrtx * 3 sqrtx = 9x (sqrt * sqrt eliminates the sqrt) 2. sqrt t * sqrt t = t 3. 3 sqrt R / 3 sqrt x = sqrt R / sqrt x area 2: a million. 4 sqrt x^2 = 4x (a million/2*2 = a million) 2. sqrt t = t^a million/2 3. 4 sqrt x^7 (reminiscent of a million: a million/2 * 7 = 7/2) so 4x^7/2 4. a million/ 5sqrt x^2 = a million/5x area 3: a million. x^2 / y^-3 = x^2 y^3 (you place a a million over y then convey it up) 2. x^3 y^-5 = x^3/y^5 3. x^2y^-4z^4 = x^2z^4 / y^4 4. x^2 / y^-a million/2 = x^2 y^a million/2 5. x^2 y^3 t^-4 z^-6 w = x^2 y^3 w / t^4 z^6 pass unfavourable exponents to the denominator desire this helps.

2016-12-10 13:50:16 · answer #2 · answered by warfel 4 · 0 0

The "exponent" in front of the radical is actually not an exponent at all. By convention, a radical with no number preceding it is a square root, but if a number exists, it refers to a root other than 2.

2006-07-24 16:06:38 · answer #3 · answered by stonecutter 5 · 0 0

jeez i dont understand your terminology and its 18 problems, do your homework for once.

2006-07-24 15:59:57 · answer #4 · answered by ConradD 2 · 0 0

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