Given a right triangle with a=3 and c=11, find b to three decimal places??? Can you figure this out?

Answer 1

Next time do your own homework, but I'm bored so I'll give u the answer.
You have to use Pythagorean therom
so b=10.583

Answer 2

This problem of a right triangle can be solved with pythagorean

The formula

a² = b² + c²

- - - - - - - - - - - - - - - - - - - - - - - - -- - - - - - - - -- - - -
Information from the statement

a = 3

c = 11

-- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Sides a and c are given and solving for b

The formula for Pythagorean Therom has to be rearanged

c² = a² + b²
-a² -a²

Subtract - a from both sides

c² - a² = b²

This is the formula to use.

b² = √11² - 3²

b² = √121 - 9

b² = √112

The number inside the radical sign √112 is called the radicand

b = 10.58300524

b = 10.583 rounded to three decimal places

The answer is 10.583

Answer 3

Pythagorean Theorem
C^2 = A^2 + B^2
11^2 = 3^2 + B^2
B^2 = 11^2 - 3^2
= 121 - 9
B^2 = 112
B = 10.583

Answer 4

10.583

3 squared + X squared = 11 squared
9+x squared = 121
X squared = 112
Square root both sides
X = 10.583

Answer 5

2.828

I used the formula a2 + b2 = c2 then manipulated it.

Answer 6

b=sqrt(121-9)
b=10.583

Answer 7

11.402