2006-07-24 13:22:16 · 11 answers · asked by Just me 1 in Science & Mathematics ➔ Mathematics
f(x) = x^2 + 1
f(-3) = (-3)^2 + 1
f(-3) = 9 + 1
f(-3) = 10
2006-07-24 13:40:30 · answer #1 · answered by Anonymous · 0⤊ 0⤋
10
2006-07-24 20:55:41 · answer #2 · answered by davidosterberg1 6 · 0⤊ 0⤋
10
2006-07-24 20:25:23 · answer #3 · answered by Michael J with wings 3 · 0⤊ 0⤋
Okay whenever you are given a similar question to that, just do the following:
From your question:
f(x) = x^2 + 1 this just general about x which can be any number.
Now you are told that you have to do f(-3) which means that you have to substitute x with -3 to get:
f(-3) =(-3)^2 + 1
f(-3) = 9 + 1
f(-3) = 10
2006-07-24 20:48:05 · answer #4 · answered by chrizere 2 · 0⤊ 0⤋
f(-3) = 10
2006-07-24 20:25:08 · answer #5 · answered by Knick A 3 · 0⤊ 0⤋
f(x) = x^2 + 1
f(3) = 3^2 + 1 = 9 +1 = 10
f(3) = 10
2006-07-25 00:11:06 · answer #6 · answered by Subhash G 2 · 0⤊ 0⤋
In put -3 in for x to arrive at the answer of 10
2006-07-24 20:31:59 · answer #7 · answered by mstang 2 · 0⤊ 0⤋
F(x)=x^2+1
F(-3)=(-3)^2 + 1
F(-3)=9 + 1 =10
2006-07-24 22:54:33 · answer #8 · answered by Anonymous · 0⤊ 0⤋
i thinks its 10
2006-07-24 20:30:44 · answer #9 · answered by dance princess 2 · 0⤊ 0⤋
yep, 10
2006-07-24 20:29:37 · answer #10 · answered by saberhilt 4 · 0⤊ 0⤋