What is the thrust of a rocket that burns fuel at a rate of 1.3 x 10^4 kg/s if the exhaust gases have a velocity of 2.5 x 10^3 m/s with respect to the rocket?
2006-07-24 07:38:42 · 3 answers · asked by Lou 1 in Science & Mathematics ➔ Mathematics
Simply multiply the two numbers.
(1.3 x 10^4 kg/s)(2.5 x 10^3 m/s) = 3.25 x 10^7 kg/(ms^2)
ANSWER: 3.25 x 10^7 Newtons
The links "Brian L" and "Vincent H" give contain a more accurate formula. This formula requires more information than you give in the question. However, usually the term we computed above is by far the most important component to total thrust. (This is mentioned in the first link.)
2006-07-24 07:43:39 · answer #1 · answered by Aaron 3 · 0⤊ 0⤋
Use the thrust equation. See below.
2006-07-24 14:42:22 · answer #2 · answered by Brian L 7 · 0⤊ 0⤋
Not enough data to compute. Need more information.
http://www.grc.nasa.gov/WWW/K-12/airplane/rktthsum.html
2006-07-24 14:49:33 · answer #3 · answered by Vincent H 1 · 0⤊ 0⤋