Can someone help? I need to find 3 industries that have volume-profit relationships. Which are implementing cost leadership strategies? Which are implementing differentiation strategies? or both? or none?
Cost leadership: focuses on gaining advantages by reducing costs below their competitors
Diff. Strategies: attributes, features, location, timing, relationships between itself and its customers, linkages within or between firms
2006-07-24 06:31:55 · 4 answers · asked by JCHERRIE48 1 in Business & Finance ➔ Other - Business & Finance
well, its asking 3 industries or markets...
2006-07-24 06:41:14 · update #1
Can you explain why you put the answers you did? I am not sure of the question itself! =) Thanks!
2006-07-24 06:45:08 · update #2
IF YOU ARE GOING TO SAY "DO YOUR HOMEWORK YOURSELF" PLEASE DO NOT RESPOND! OBVIOUSLY I DO NOT KNOW HOW TO ANSWER THIS QUESTION!!
2006-07-24 06:57:16 · update #3
You should be asking about companies rather than industries. In the same industry you can have cost leaders and differentiators. Let's take the auto industry for example; Hyndai/Kia is a cost leader, while Porsche is clearly a differentiator.
2006-07-24 06:39:10 · answer #1 · answered by NC 7 · 0⤊ 0⤋
What you are describing is almost any firm that is producing commodities. In order to succeed a commodity oriented business has to have the highest production with the lowest costs. Look at ethanol companies, fertilizer companies, almost anything agriculture related. Pork industry is a prime example of what you seek. Engery companies also would be good, coal, oil, etc etc. I hope this helps
2006-07-24 06:42:49 · answer #2 · answered by erik c 3 · 0⤊ 0⤋
The purpose of this homework is to train you in conducting research. Then, go to the library, use the Internet, read publications about finance; in other word, do your homework. Don't cheat yourself.
2006-07-24 06:45:14 · answer #3 · answered by dC4 2 · 0⤊ 0⤋
int[fee/(fee+sint)]= int[fee(fee-sint)/(cos^2 t-sin^2 t)] i.e. with the aid of rationalizing the denominator. So we get int[(cos^2 t-fee sin t)/(cos^2 t-sin^2 t)] =int[cos^2 t/(cos^2 t-sin^2 t)] - 0.5int[sint2t/cos2t] =int[cos^2 t/(2cos^2 t-a million)] - 0.5int[sint2t/cos2t] placed cos^2 t=a^2 and combine the 1st area wrt to a and the 2d area is straight away int[tan2t] First area is int[ - a^2 / ( (2a^2 -a million) * sin t) ] it is elementary to do
2016-10-08 06:39:36 · answer #4 · answered by ? 4 · 0⤊ 0⤋