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a 0.5 mol of N2O2 in a 1liter beaker, decompose to NO2, process is first order with rate constant 4500/s at 25 degreesC.
How many molecules of N2O4 will remain after decomposing for 1.2 minutes?
show a sol'n plz, tnx

2006-07-24 06:01:06 · 2 answers · asked by Mark Curtis 2 in Science & Mathematics Chemistry

2 answers

d[N2O4]/dt=k*[N2O4]

d[N2O4]/[N2O4]=k dt

Integrate from 0 to 72 seconds

ln ([N2O4]/.5M)=4500/sec* (72s)

Solve from there, do the logrithms correctly

Then multiply by Avagradro's number to get #molecules from moles.

2006-07-24 07:34:07 · answer #1 · answered by Iridium190 5 · 0 0

you need to give the equation for the first order rxn so that I can plug in the numbers

its not that hard you just need to put numbers into an equation and solve

2006-07-24 13:19:33 · answer #2 · answered by joedog 1 · 0 0

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