2006-07-24 02:41:46 · 10 answers · asked by menen d 1 in Science & Mathematics ➔ Chemistry
8.
2s^2 2p^6 (2+6=8).
2006-07-24 09:26:45 · answer #1 · answered by Ravi 2 · 2⤊ 0⤋
8
2006-07-24 02:45:33 · answer #2 · answered by cimarch 2 · 0⤊ 0⤋
The number of electrons that can reside in a shell is equal to 2*n^2, so for this case equal 8
2006-07-24 02:46:34 · answer #3 · answered by RS 4 · 0⤊ 0⤋
for n=2 we have
l=0,l=1 (2S and 2P orbitals)
for l=0 we have m=0 which is one orbital (2 electrons)
for l=1 we have m=-1,m=0,m=1 which are 3 orbitals (6 electrons)
total number of electrons: 8
guess everyone was right.
2006-07-24 03:58:41 · answer #4 · answered by mashkas 3 · 0⤊ 0⤋
follow the formula 2n^2
so maximm electron in second shell that can exist are 8
hope it will help
remember the formula 2n^2
2006-07-24 02:49:00 · answer #5 · answered by ghulamalimurtaza 3 · 0⤊ 0⤋
the shell with n=2 is the L-shell and it can only acommodate 8 electrons.thank you
2006-07-24 03:01:01 · answer #6 · answered by Anonymous · 0⤊ 0⤋
maximum number of electrons:
s=2
p=6
d=10
f=14
g=18
h=22
2006-07-27 01:33:08 · answer #7 · answered by Yonamaria 2 · 0⤊ 0⤋
8.........u can get the answer by refering to the periodic table
or........
1s
2s2p
3s3p3d
4s4p4d4f
s,p,d,f are the orbitals that can exist in each shells:-
s=max 2e'
p=max 6e'
d=max10e'
f=im not sure....hope u understand
2006-07-25 19:53:35 · answer #8 · answered by balu 1 · 0⤊ 0⤋
use the formula
2n*2
while n=no of shell of an atom
2006-07-24 05:03:34 · answer #9 · answered by scholar 1 · 0⤊ 0⤋
8. ( 2s^22p^6)
2006-07-24 04:25:28 · answer #10 · answered by papa 2 · 0⤊ 0⤋