The answer is A) 12. If the point is 6 centimeters from the outside of the circle, then it is 15 cm from the center. There is a right triangle formed by the segment connecting the center to the outside point, the segment connecting the outside point to the point of tangency (this is the one we want to find the length of), and the radius from the center to the point of tangency. Using the pythagorean theorem, we get:
15^2 = 9^2 + x^2
225 = 81 + x^2
144 = x^2
x = 12
The mistake made by the previous answerers was substituting the two known values (15 and 9) in for a and b in the pythagorean theorem. However, 15 represents the hypotenuse of the triangle, so it should be substituted for c.
2006-07-23 16:09:30
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answer #1
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answered by mathsmart 4
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mathsmart is right
If C is the centre and P is the point 6 cm from the circle
CP = 6+9 = 15
If PQ is the required length of the tangent
CPQ is a right angled triangle with right angle at Q
therefore
PQ = sqrt{CP^2 - CQ^2}
= sqrt{15^2 - 9^2} note that CQ = radius =9}
= 12 cm
2006-07-23 16:25:21
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answer #2
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answered by qwert 5
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The radius of the circle is 9 cm and the tangent is drawn from 6 cm distance for the circumference of the circle.
The tangent is always perpendicular to the radius
Tha tangent is the hypotenuse of the triangle formed by the ponint to the cnetre ofthe circle and the point of contact of the tangent to the centre
Length of tangent = sq rt of 15^2+9^2
sq rt of 306
= 17.49 cm
2006-07-23 16:49:01
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answer #3
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answered by Subhash G 2
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12 cm by inspection.
It's a 3-4-5 right triangle
2006-07-23 18:38:27
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answer #4
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answered by Fred S 2
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Mathsmart is exactly correct. The answer is a-12.
2006-07-23 16:20:36
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answer #5
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answered by eyebum 5
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d) none of these
Answer: Square root(15squared + 9squared} = ca 17
2006-07-23 15:58:39
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answer #6
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answered by Swaminathan A 1
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its d....i think its square root of 141, but not positive. my math is a little rusty during the summer.
2006-07-23 15:50:04
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answer #7
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answered by Llovesyou 2
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D. Not enough info. You have to make too many assumptions to get an answer.
2006-07-23 16:16:30
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answer #8
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answered by Anonymous
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D
2006-07-23 15:48:26
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answer #9
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answered by Byron M 1
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