the volume of the sample change?
2006-07-23 15:35:53 · 6 answers · asked by Byron M 1 in Science & Mathematics ➔ Chemistry
Ideal gas, V increases 4/3 or 1.333 times
PV = nRT
V = (nR)*(T/P) so assuming nR remains constant, the ratio of T/P is how many times V decreases or increases
2006-07-23 15:41:07 · answer #1 · answered by ic3d2 4 · 1⤊ 0⤋
It will increase to 4/3 of its original volume.
2006-07-23 22:41:13 · answer #2 · answered by zee_prime 6 · 0⤊ 0⤋
I'd use the Combined Gas Law: P1 x V1 / T1 = P2 x V2 / T2.
The question states that T2 = 4T1 and that P2 = 3P1. Make the substitutions and solve for V2 in terms of V1.
2006-07-24 02:54:15 · answer #3 · answered by rb42redsuns 6 · 0⤊ 0⤋
Volume would increase 4/3 times, i.e. 33.3% larger
2006-07-23 22:46:35 · answer #4 · answered by Swaminathan A 1 · 0⤊ 0⤋
let's take a look at your basic gas equation
pV = nRT
n is constant as it is dependant on the amount of gas present.
Thus we solve for V
V = nRT/p
V_1 = nR(T_1/p_1)
V_2 = nR(4T_1/3p_1)<--- from your question
Thus,
V_2 = (4/3)nR(T_1/p_1) or (4/3) V_1
The factor is 4/3 the initial volume.
2006-07-23 22:43:18 · answer #5 · answered by polloloco.rb67 4 · 0⤊ 0⤋
using the ideal gas equation. pv=rt. it would then be pv=t since r is a constant. and v= 4/3
2006-07-23 22:43:10 · answer #6 · answered by marcos m 2 · 0⤊ 0⤋