2006-07-23 14:29:50 · 17 answers · asked by cammer_14@sbcglobal.net 1 in Computers & Internet ➔ Internet
yeah right! this is the email you got right look at his website http://www.helpbytes.co.uk/yhoax.php
yahoo Alert: Yahoo is shutting down on August 17,2003 because they are running outta space and all the names are getting took up, so pass this around if you don't want your name to be deleted from Yahoo. If you don't pass this on, then your Yahoo will be shut down for good. Those that don't send, your name will be deleted August 17,2003, thanks, Yahoo Board Leader, Tom Buslowski
2006-07-23 14:31:15 · answer #1 · answered by livingforjesus231 5 · 0⤊ 0⤋
i have no idea i have also heard that i hope not i want to stay in touch with all the great people i have met... i heard there getting tired of giving im messengers for free. .. there not gettin rid of it i think there just going to start making people pay for it..
take care
2006-07-23 14:32:33 · answer #2 · answered by *~BabiGurl~* 3 · 0⤊ 0⤋
The rumor that yahoo is going to close down messenger has been handed around the web for years. it isn't genuine. contained in the destiny in case you acquire the form of caution purely delete it.
2016-10-15 03:21:22 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Yes, it is on August 16th
2006-07-23 14:31:55 · answer #4 · answered by Bill 6 · 0⤊ 0⤋
I Dont Know But That Would Be Horrible...
2006-07-23 14:31:18 · answer #5 · answered by ekilps_08_25_93 2 · 0⤊ 0⤋
You got that too huh. Its just a chain message dont worry about it.
2006-07-23 14:32:29 · answer #6 · answered by ♣♣Brick♠♠ 2 · 0⤊ 0⤋
I've been asking and from what I found out its a roomer... RON
2006-07-23 14:31:52 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Ouch, that will take a bite outta crime ! Have to wait and see.
2006-07-23 14:31:31 · answer #8 · answered by ₦âħí»€G 6 · 0⤊ 0⤋
I doubt it but this is the first i've heard of this
2006-07-23 14:39:50 · answer #9 · answered by Anonymous · 0⤊ 0⤋
I hope not i luv yahoo!
2006-07-23 14:31:56 · answer #10 · answered by Angel Baby 3 · 0⤊ 0⤋