Let the 2 numbers be x and y.
Then according to the given question, x + y = 8.5
and xy = 18
First equation gives, y = 8.5 - x --------- (1). Substitute this in the second equation. Which implies x(8.5 - x) = 18.
gives, 8.5x - x^2 = 18
gives, (17/2)x - x^2 = 18 (Taking LCM)
gives, 17x - 2 x^2 = 36
multiplying with "-" on both sides.
gives, 2 x^2 - 17x = -36
gives, 2 x^2 - 17x + 36 = 0
gives, 2 x^2 - 8x - 9x + 36 = 0
Solving this gives x = 4 , 4.5.
Substituting these values in equation 1:
When x = 4. y = 8.5 - 4 = 4.5
When x = 4.5. y = 8.5 - 4.5 = 4
Therefore the two numbers are 4, 4.5
Hope you understood the explanation.
2006-07-23 14:10:03
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answer #1
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answered by Sherlock Holmes 6
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It would be real nice if the numbers were rational numbers... if not, use quadratic equation to solve
x^2 - 8.5 x + 18 = 0
Because the sum is 17/2, we look a half-integer that divide 18.
18 = 1/2 * 36, but sum is 73/2
18 = 1 1/2 * 12, but sum is 27/2
18 = 4 1/2 * 4, and sum is 17/2 BINGO
2006-07-23 18:07:22
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answer #2
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answered by dutch_prof 4
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This is a problem in Freshman Algebra. Start with x+y=8.5 and xy=18. Expand it from there and you should get an answer. It's really a quite simple problem if you remember that whole numbers may not be the answers.
2006-07-23 13:07:17
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answer #3
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answered by miyuki & kyojin 7
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Sherman's answer is truly impressive, but one can determine the answer almost intuitively. I tried algebra, but got stuck. I realized that one of the numbers was fractional and one of the numbers that 18 was divisible by could not produce another integer. That excluded 1, 2 and 3. 4 was the first number I could divide into 18 to reach a nice fraction, which multiplied by another integer, 4, gave the answer.
This was fun.
2006-07-23 19:17:15
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answer #4
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answered by hellbent 4
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let the numbers be x and y
x+y = 8.5 and xy = 18
or x + 18/x =8.5
or x^2 - 8.5x + 18 = 0
or x^2 - 4.5x - 4x + 18 = 0
or x(x - 4.5) - 4(x - 4.5) = 0
or (x-4.5)(x-4) = 0
or x = 4.5 and x = 4 or the numbers are 4.5 and 4
2006-07-23 17:24:46
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answer #5
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answered by Subhash G 2
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x+y=8 and xy=18
x=8-y :::subtract both sides of equation by -y
(8-y)y=18::: substitute x from above
8y-y^2=18 :::distributive property
y^2-8y= - 18 :: multiply both sides by -1
y^2-8y+16= - 18+16 :::complete the square
(y-4)^2 = -2
y-4=+_-2^.5
no real number solution
2006-07-24 02:13:56
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answer #6
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answered by greatire 2
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x + y = 8.5
xy = 18
y = 8.5 - x
x(8.5 - x) = 18
8.5x - x^2 = 18
x^2 - (17/2)x + 18 = 0
x = (-b ± sqrt(b^2 - 4ac))/2a
x = (-(-17/2) ± sqrt((-17/2)^2 - 4(1)(18)))/(2(1))
x = ((17/2) ± sqrt((289/4) - 72))/2
x = ((17/2) ± sqrt((289/4) - (288/4))/2
x = ((17/2) ± sqrt((289 - 288)/4))/2
x = ((17/2) ± sqrt((1/4)))/2
x = ((17/2) ± (1/2))/2
x = ((17/2)/2) ± ((1/2)/2)
x = ((17/2)/(2/1)) ± ((1/2)/(2/1))
x = ((17/2)*(1/2)) ± ((1/2)*(1/2))
x = (17/4) ± (1/4)
x = (17/4) + (1/4) or (17/4) - (1/4)
x = ((17 + 1)/4) or ((17 - 1)/4)
x = (18/4) or (16/4)
x = (9/2) or 4
ANS : 4.5 and 4
2006-07-23 15:59:27
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answer #7
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answered by Sherman81 6
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2 equations 2 unknowns. Simple algebra. Sounds like a simple homework problem.
2006-07-23 12:56:15
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answer #8
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answered by gtoacp 5
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x+y=8.5
xy=18; x=18/y
x+y=8.5
18/y+y=8.5
y(18/y+y=8.5)
18+y^2=17y/2
2(18+y^2=17y/2)
36+2y^2=17y
2y^2-17y+36=0
(2y-9)(y-4)=0
2y-9=0 or y-4=0
2y=9 y=4
y=9/2
y=9/2 or y=4
2006-07-24 00:22:55
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answer #9
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answered by lois lane 3
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4.5+4=8.5
4.5*4=18
2006-07-23 12:54:50
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answer #10
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answered by Anonymous
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