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A steel beam is suspended completely under the water by a cable so that it hangs vertically.
Another identical beam is suspended horizontally under the water by a cable attached to the center of the beam. Please provide a reason. Neglect the minimal change in density of water with depth.

2006-07-23 10:55:08 · 5 answers · asked by Anonymous in Science & Mathematics Physics

5 answers

same.......they both displace the same mass of water.

if vertical, smaller top/bottom area but greater change in pressure due to greater depth difference between top and bottom.

if horizontal, large top/bottom area but smaller change in pressure between top and bottom due to smaller depth change.

2006-07-23 11:06:22 · answer #1 · answered by Anonymous · 3 1

The only reason one would have more bouyancy is if the changes in water density were considered. In a uniform bath, two identical steel beams held underwater would have the same bouyancy. This is a definition of what bouyancy is. Given that, the upward force on the cables would be equal, because they are both countering the same forces (gravity and bouyancy).

2006-07-23 11:02:10 · answer #2 · answered by soulinverse 4 · 0 0

Fb = pgV, where p is the density of the liquid, g is gravitational acceleration and V is the the submerged volume of the beam. Since the liquid is the same, the gravitational acceleration is the same, and the same volume is submerged (that is, the entire beam is submerged), both beams experience the exact same buoyant force.

2006-07-23 11:06:55 · answer #3 · answered by عبد الله (ドラゴン) 5 · 0 0

sure countless, the final prevalent having been 17 october 1989 whilst there replaced right into a considerable earthquake in California in the time of a "international series" baseball game. Had it no longer occured my brother woulda been on Nightline with Ted Koppel afterwards.

2016-12-10 12:58:51 · answer #4 · answered by ? 4 · 0 0

I would have to say they are identical as they displace the same amount of water, if you remove the density change
buoyancy = weight of displaced water = volume x density x g

2006-07-23 11:03:06 · answer #5 · answered by mononcue 1 · 0 0

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