2006-07-23 05:04:08 · 13 answers · asked by LtTuvok1701 2 in Science & Mathematics ➔ Mathematics
there are 4536 numbers
2006-07-23 05:08:47 · answer #1 · answered by Prakash 4 · 0⤊ 1⤋
For the first digit, you have 10 choices. For the second digit, 9; and so forth. The total number of permutations is therefore
10 P 4 = 10 * 9 * 8 * 7 = 5040.
2006-07-23 08:27:26 · answer #2 · answered by dutch_prof 4 · 0⤊ 0⤋
If you are mathematically inclined: Factorial 10 divided by factorial (10-4) given that the internal arrangement matters. That is 0987 is different from 8079. So its 10!/(10-4)!
First place one of 10 ways x Second place one of 9 ways x Third place one of 8 ways x Fourth place one of 7 ways = 10x9x8x7 = 5040.
And Naveen you are probably wrong, the asker didn't specify if the number has to have a VALUE. The digits can be simply symbols in which case 5040 is the correct answer. Only if you specify that the resulting digits have to have a value, then the ZERO can't occupy the left most place.
2006-07-23 05:33:21 · answer #3 · answered by The_Dark_Knight 4 · 0⤊ 0⤋
0 - 9 gives ten digits.
(10 x 9 x 8 x 7) / (1 x 2 x 3 x 4) =
5040 / 24 = 210
2006-07-23 05:40:58 · answer #4 · answered by Brenmore 5 · 0⤊ 0⤋
If 1234 is different from 4321 then 10*9*8*7 = 5040
If they count as the same (being the same four numbers albeit in a different order) then (10*9*8*7)/(4*3*2*1) = 5040/24 = 210
2006-07-23 05:21:41 · answer #5 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
If you mean none of the resulting 4-digit numbers can be repeated, it's 10,000 (counting 0000). If you mean none of the digits can repeat within a number then it's 5040 (10*9*6*7).
2006-07-23 05:09:22 · answer #6 · answered by Arrow 5 · 0⤊ 0⤋
10*9*8*7.Since first can be arranged in 10 ways second can be arranged in 9 ways and third can be arranged in 8 and fourth can be arranged in 7.Hence the total no is their product as given.
2006-07-23 05:35:59 · answer #7 · answered by vishvesh 1 · 0⤊ 0⤋
there are
9*9*8*7=4536 nos.
zero cannot occupy the thousand's place.
so the 1000th place can be occupied by only 9 nos(1,2,3,4,5,6,7,8,9,).
it is NOT 10*9...... as indicated by some people.
2006-07-23 05:26:28 · answer #8 · answered by Anonymous · 0⤊ 0⤋
LOL... it would be number from 0000 to 9999 GOOD LUCK You only get 3 tries and then the phone is what is called "bricked" - you have to purchase a new phone after that.
2016-03-27 04:01:32 · answer #9 · answered by Anonymous · 0⤊ 0⤋
Listen to arrow
2006-07-23 05:15:52 · answer #10 · answered by Roxi 4 · 0⤊ 0⤋
Who are you trying to call that you don't have the number for? lol.
2006-07-23 05:08:30 · answer #11 · answered by Jenn 6 · 0⤊ 0⤋