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You are lying 120ft away from a tree that is 50ft tall. You look up at the top of the tree.How far is your hear from the top of the tree in a straight line?

2006-07-23 03:03:32 · 11 answers · asked by Anonymous in Education & Reference Homework Help

11 answers

You need to draw a triangle to understand this better. Draw a horizontal line - one end of which is where you are lying, and the other end is the bottom of the tree. Write the length - 120 ft - below this line. From the end of this line which is the bottom of the tree, draw a perpendicular vertical line. This line is the tree, write 50 ft next to it. Now join the top of this line and the other end of the horizontal line (where you are lying) by drawing a straight line. Now you have a right angled triangle. What you have to find now is the length of this last slanting line that you have drawn - which is the distance between the top of the tree and your hear (your question).

Use the Pythagoras theorem to find the solution. The theorem : a (squared) + b (squared) = c (squared). Here 'a' is the horizontal line - 120ft, and 'b' is the vertical line - 50 ft. 'c' - the slanting line - is what you have to find. Hence:

120 (squared) + 50 (squared) = c (squared)
14400 + 2500 = c (squared)
16900 = c (squared)
130 = c

Therefore 'c', which is the distance between your hear and the top of the tree, is equal to 130 feet.

2006-07-23 03:48:59 · answer #1 · answered by annie7 2 · 1 0

This problem can be solved by Pythagoerean Theorem

c² = a² + b²

Insert 120 into the a position

insert 50 into the b position

C² = √120² + 50²

C² = √1440 + 2500

The results of the square of 120 = 1440 and 50 square equal 2500 inside the radical sign

C² = √16900

Adding the sum of 1440 + 2500 equal 16900 inside the radical sign.

The number inside the radical sign √ 16900 is call the radicand

C = 130

The expression 130 is called the square root

The answer: from your head to the top of the tree is 130 ft.

Tfhe solution set is {130}

2006-07-23 11:01:53 · answer #2 · answered by SAMUEL D 7 · 0 0

The tree is one side of the triangle. The line from the base of the tree to your head is another. You can divide both sides by 10 to get 12 and 5. The line in the air from your head to the tree top is the long side, or hypotenuse.

a squared + b squared = c squared.
25 + 144 = c squared
c squared = 169
c = 13
Multiply by 10 to make up for dividing by 10 before to make "C" 130.

3-4-5 and 5-12-13 are both well-known right triangles. They work in any proportion. 6-8-10 is still 3-4-5; so is 300-400-500 or 21-28-35.

2006-07-23 10:14:10 · answer #3 · answered by Adam Zapple 2 · 0 0

use pythagorean therom. A^2 +B^2=C^2
The 120 ft and the 50ft are both legs so they would be plugged into a and b. you should get 16900. But you still have to get rid of the c^2 so you do the square root of 16900 which comes out to be 130.
*Draw a picture when you get these kinds of problems. It helps.

2006-07-23 15:57:52 · answer #4 · answered by ¤DS¤ 4 · 0 0

Easy. That's a right triangle, with sides of 120 and 50. The formula is a2+b2=c2, with a and b being the sides and c the hypotenuse, which is what you're looking for.

50^2+12-^2=c2
2500+14400=c2
16900=c2
130=c

130 ft.

2006-07-23 10:16:27 · answer #5 · answered by enaronia 2 · 0 0

Use the Pythagorean theorem
A(squared) + B(squared) = C(squared)
120 (squared) + 50 (squared) = C (squared)
14400 + 2500 = C squared
16900 = C squared
130 ft = C
C=the distance you were looking for

2006-07-23 10:13:05 · answer #6 · answered by sc1120 3 · 0 0

130 ft

2006-07-23 10:07:24 · answer #7 · answered by nalan 3 · 0 0

no, that's too easy. Draw a picture and then figure it out for yourself - it is thruly the only way to learn, and you won't have Yahoo answers when you take the test. HINT.... Assume a right triangle.

2006-07-23 10:08:04 · answer #8 · answered by ceprn 6 · 0 1

sqrt(120^2 + 50^2)
130ft

2006-07-23 10:17:19 · answer #9 · answered by Anonymous · 0 0

130 feet...pythagorean theorem...a squared + b squared = c squared

2006-07-23 10:07:30 · answer #10 · answered by sillynoodle101 2 · 0 0

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