because the freezing point remains the same and when the liquid reaches it's freezing point it will almost instantly freeze, where as a solid can be heated past its melting point and it still might not immediately melt, take for instance if you take some water and cool it down to 0 degrees centigrade it will, when it reaches exactly o degrees form ice crystals on the surface of the water, but if you take a ice cube you can put it in the oven and it will mely very quickly at 98 degrees centigrade even though its melting temperature is much lower.
2006-07-23 06:08:42
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answer #1
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answered by Anonymous
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That is contingent upon the substance you are testing. Measuring the freezing point of water for example is quite easy; however, measuring the melting point of lead(pb), might prove to be more challenging.
2006-07-23 09:11:41
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answer #2
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answered by tigranvp2001 4
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Notice: The freezing point and melting point of a substance are THE SAME TEMPERATURES! Liquid water freezes to form ice at 0 degrees Celsius (32 degrees Fahrenheit) and ice melts to form liquid water at SURPRISE! 0 degrees Celsius (32 degrees Fahrenheit.
2006-07-23 09:16:46
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answer #3
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answered by physandchemteach 7
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melting point is the same as the freezing point.in the case of water these are equal to 0 deg. celsius.
perhaps for the ease in observation we use the freezing point.
2006-07-23 09:11:53
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answer #4
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answered by rumradrek 2
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1) It freezes easier than it melts
2) The melting point can be so high that it's difficult to get temperatures high enoug to melt it.
2006-07-23 09:07:02
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answer #5
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answered by Anonymous
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I think it's because it's easier to achieve thermal equilibrium in a liquid (you can stir the liquid with the thermometer or shake the test tube) than in a solid. It's also easier to observe the beginning of the phase change if your liquid starts changing to a solid.
2006-07-24 03:00:48
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answer #6
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answered by rb42redsuns 6
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Try sticking a thermometer/temperature probe in an ice cube.
Now try sticking it in water.
Make sense now?
2006-07-23 10:34:02
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answer #7
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answered by craftman 2
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