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6 answers

Well, if I divide the 40-gon into 40 triangles all meeting at the center of the 40-gon, then the angle (at the vertex will be) 360/40 = 9 degrees which means that the other two angles in each triangle and each interior angle is 180 - 9 = 171 degrees and since there are 40 such angles, the sum of all 40 of the interior angles is 171*40 = 6840 degrees.

You can also use this (general formula).
The sum of all the interior angles of ANY polygon (it doesn't have to be regular) in degrees is
180 * (n-2) where n is the number of vertices.
Which, of course, gives you the same answer as above.

2006-07-22 17:22:37 · answer #1 · answered by The Prince 6 · 5 0

180 X (n-2) = 180 X (40-2) = 180 X 38 = 6840 degrees.

2006-07-23 00:28:49 · answer #2 · answered by Shehan 4 · 0 0

(40 - 2) x 180 = 6840 degrees

2006-07-23 04:05:02 · answer #3 · answered by dutch_prof 4 · 0 0

180*38, you can at least do the math...

2006-07-23 00:25:40 · answer #4 · answered by veritas 2 · 0 0

I am not doing your homework for you.....

2006-07-23 00:22:44 · answer #5 · answered by lilly 2 · 0 0

do your own homework

2006-07-23 00:53:14 · answer #6 · answered by Chie 5 · 0 1

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