2006-07-22 17:02:24 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Astronomy & Space
Yes. 17,500 mph is orbital velocity. Any slower and the space craft will fall to Earth before completing the first half orbit.
Escape velocity is even faster. You need 25,000 mph to escape Earth and go to the Moon or Mars or whatever.
2006-07-22 17:09:20 · answer #1 · answered by campbelp2002 7 · 0⤊ 0⤋
Shuttle's angular velocity is the same as the Earth's. The tangential velocity will depend upon distance. Orbiting is nothing more than free falling at the same rate as a point on the Earth is moving. The shuttle and Earth's surface are "falling" at the same rate thereby creating a stable orbit.
2006-07-23 01:07:51 · answer #2 · answered by Richard B 4 · 0⤊ 0⤋
Orbital velocity is the speed you happen to be orbiting at. That will vary depending on how far out you are. It's around mach 25 in LEO. It's much slower at geosynchronous. And of course, the moon orbits once per month.
2006-07-23 00:11:39 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the velocity required for a stable orbit is different depending on the mass of the two bodies and the distance from the orbited body
2006-07-23 00:06:04 · answer #4 · answered by enginerd 6 · 0⤊ 0⤋
Orbital velocity is DIFFERENT from excape velocity. Orbital velocity can change radically depending on how far away and how large the object (look at the moon!)
Escape velocity is about 17,000 mph.
2006-07-23 00:19:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋
no, the orbital velocity is the velocity which a body possess when it moves around (like earth around sun) another in a orbit.
orbital velocity = 2 *pi* R/T
R= radius of the orbit
T= time needed to complete one ratation ( 1 year for earth around sun)
2006-07-24 15:13:27 · answer #6 · answered by rinjam 2 · 0⤊ 0⤋
nope, thats the speed that a satellite orbits its planet.
escape velocity is what space flying machines need to achieve.
2006-07-24 15:50:27 · answer #7 · answered by Dirk Wellington-Catt 3 · 0⤊ 0⤋
This one is easy. The formula is: sqrt(GM/R)
G is the gravitational constant: 6.67259e-11 meters per second per second.
M is the mass of the bodies in tonnes. (The earth is about 5.974e21 tonnes.)
R is the radius in kilometers. (The AVERAGE radius of the earth is about 6378 kilometers.)
Now lets put a satellite in orbit 300 kilometers up. (That would be a radius of 6678 kilometers form the center of the earth.)
sqrt(6.67259e-11 x 5.974e21 tonnes / 6678 kilometers)
The satellite will orbit at 7726.034 meters per second.
2006-07-23 03:06:08 · answer #8 · answered by longhairabsalom 2 · 0⤊ 0⤋
It's escape velocity but i suppose it could also be called that.
2006-07-23 00:05:48 · answer #9 · answered by Jake S 5 · 0⤊ 0⤋
I guess u could call it that. commonly its escape velocity.
2006-07-23 00:41:33 · answer #10 · answered by pbmaze 3 · 0⤊ 0⤋