What is the volume of 0.1 mol of sulphuric acid which would react with 20 cm³ of 0.5 mol/dm³ sodium carbonate?

Answer 1

The chemical equation for the reaction is

H2SO4 + NA2CO3 = NA2SO4 + CO2 + H2O

find the mol of sodium carbonate that's used:
0.5mol/dm³ x 0.02dm³ = 0.01 mols

Since the ratio of acid to carbonate used is 1:1, this means that the number of mols of H2SO4 used is 0.01mols as well.

Since there is 0.1mol of acid used it is in excess. There would be (0.1 - 0.01)mol of acid left = 0.09mol

As for the volume that would react, i think you may be lacking is some information, like maybe the concentration of the acid used or something. This is as far as i can get and hope that this'll help.