Are you good at algerba? Test your skills?

Question

Determine the equivalent resistance of a infinite series-parallel resistor network. (series-parallel-series-parallel ect.) See how go you are at doing algebra. You have to show your work to get full credit (10 points)

Answer 1

the resistance of the network will aproach zero
http://mathforum.org/library/drmath/view/51490.html

Answer 2

let r be the resistance value ohms, for all the resistances parallel or in series. Take the first two in series and the following two in parallel. The equivalent resistance is r+r+1/(1/r+1/r)=2.5r.
repeat this n times and obtain 2.5 nr=R the equivalent resistance.
If n approaches infinity R does the same.

Answer 3

It depends how many components you put in each series and parallel part. Since you did not specify that, I take the challenge and use variables m and n for these numbers.

Let R0 be the individual resistance, and start with series circuit:

R1 = m . R0

then make a parallel circuit:

R2 = R1 / n = R0 . m/n

continuing like this, we find
R(2k-1) = R0 . (m/n)^k / m
R(2k) = R0 . (m/n)^k

This goes to zero if mn. Assume therefore that m = n, then the equivalent resistance is equal to the individual resistance as long as the number of parallel and series steps are equal

Answer 4

Why show your work for something that's common sense?

For an infinite series of resistors in series, regardless of the other combination it's gonna be zero.

wtf man.

Answer 5

This is going to be a reverse treatment quasi-experiment! P decreases as t->infinite, yet is always positive for t+n.

If (%n== PointR) {
14.01 in 406
}
else {
Ignore;
}



Just kidding...

Answer 6

please anser to my 'what does this dream means' question at mythology & folklore.