Can someone help me figure this one out?
2log(4)9 - log(2)3
****the number in parentheses should be subscripts****
2006-07-22 09:02:55 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
I cant seem to figure out how to simplify the expression. Is there a log rule i'm forgetting?
2006-07-22 09:16:07 · update #1
yup its base 4 for 2log9 & base 2 for log3
2006-07-22 09:17:19 · update #2
Note that log base b of x, is equal to log x/log b, where log represents the logarithm in any base. Thus:
2log₄ 9 - log₂ 3
2 log 9/log 4 - log 3/log 2
2 log 9/log (2²) - log 3/log 2
2 log 9/(2 log 2) - log 3/log 2
log 9/log 2 - log 3/log 2
(log 9 - log 3)/log 2
log (9/3)/log 2
log 3/log 2
log₂3 ≈ 1.584962500721
2006-07-22 09:27:09 · answer #1 · answered by Pascal 7 · 3⤊ 1⤋
is the sum 2 log 9 to the base 4 minus log 3 to the base 2?
please confirm
2006-07-22 16:15:32 · answer #2 · answered by raj 7 · 0⤊ 0⤋
Are you so lazy to do your math homework?
2006-07-22 16:43:41 · answer #3 · answered by Anonymous · 0⤊ 0⤋
=2*(1.585)-1.585=1.585=log(2)3=log(4)9, etc.
2006-07-22 16:11:44 · answer #4 · answered by Dog_on 1 · 0⤊ 0⤋
figure it out yourself
2006-07-22 16:07:39 · answer #5 · answered by Anonymous · 0⤊ 0⤋
log30
2006-07-22 16:06:43 · answer #6 · answered by Doug B 1 · 0⤊ 0⤋
sorry I sucked at math,but thanks for the 2 points...
2006-07-22 16:06:35 · answer #7 · answered by gladys 3 · 0⤊ 0⤋