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when a reaction is exothermic, a decrease in temp. will favor the reaction and more product will be formed and the reactant will decrease...and as Kc= [conc. of products]/[conc. of reactants]. So as the conc. of product is more than the reactant..kc will be a bigger no..hence Kc will be more.

2006-07-22 13:14:53 · answer #1 · answered by sherin 1 · 3 0

When circumstances change, the equilibrium will shift to oppose the change.

If the temperature decreases, the equilibrium will shift in such a way that more heat is produced. In an exothermic reaction, it will favor the products and shift to the right, increasing the Kc.

2006-07-22 11:52:27 · answer #2 · answered by dutch_prof 4 · 0 0

BY lowering the temperature the Kc will increase. Because the reaction goes ahead.

2006-07-22 09:58:03 · answer #3 · answered by Anonymous · 0 0

All I know is if a reaction is exothermic(exit) then temperature is leaving the system to the surrounding. Therefore, the tempature of the system is decreasing and the temperature of the surroundings is increasing.

2006-07-22 09:52:35 · answer #4 · answered by cfaustin32 1 · 0 0

a million. verify out an exothermic rx as A + B ---> C + D + warmth in case you do away with warmth, i.e. decrease temp, the rx will make greater products. A 2. The expression for ok for rx A + B <---> C + D is high-quality = [C][D]/[A][B] If ok

2017-01-03 09:18:06 · answer #5 · answered by ? 3 · 0 0

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