In aerobics class the teacher indicates the sudents exercise heart rate is 60% of thier maximum heart rate, where the maximum heart rate is 200 minus thier age?
A) determine the equation that gives exercise heart rate E in terms of age A
B) Use the equation to find the exercise heart rate of a 22 year old student.
2006-07-22 08:42:46 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
r = 0.6(200 - a), where r = exercise heart rate and a = age of individual
For a 22-year-old, r = 0.6(200 - 22) = 0.6*178 = 106.8
I had always been told that maximum heart rate is 220 - a. That makes more sense, as a heart rate of 106.8 doesn't seem like an aerobic heart rate. But for the data you provided, it is correct.
2006-07-22 11:59:58 · answer #1 · answered by jimbob 6 · 0⤊ 0⤋
The equation
Exercise heart rate = (Heart rate minus age) times 60%
E = (200 - 22) x 60%
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Exercise rate using the Formula
first convert 60% to decimal
60% = 60/100 = 0.6
Percent to decimal: divide 60/100 equals 0.6
E = (200-22)(0,6)
subtract 200-22 = 178 in the formula
E = (178)(0,6)
E = 106.8
The exercise heart rate is 106.8 beats
the answer is 106.8
2006-07-22 16:45:22 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
A) E=(200-A) x .60
B) E=(200-22) x .60
E=178 x .60
E=106.8
2006-07-22 17:36:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I am a cardiologist and just to correct the teacher, the actual maximum predicted heart rate for a person is (MPHR) 220-age. so the number is 220 not 200. After that you can take whatever percentage you need. 85% is the maximum you need to achieve for the purpose of an exercise strees test, to check for ischemia. Cardio workouts aim at between 60 to 70 % (aprox)
2006-07-22 16:55:49 · answer #4 · answered by MiKe 3 · 0⤊ 0⤋
Part A is a straightforward translation of the text into a formula:
E = 60% of (200 - A) = 0.6 x (200 - A)
If you want you can simplify this by expanding,
E = 120 - 0.6 A
For part B, substitute A = 22:
E = 120 - 0.6 x 22 = 120 - 13.2 = 106.8
2006-07-22 15:58:55 · answer #5 · answered by dutch_prof 4 · 0⤊ 0⤋
A)
200 - age = 200 - A
Exercise rate is 60% of (200 - A)
E = .6(200 - A)
B)
E = .6(200 - 22) = .6(178) = 106.8 [beats/minute]
2006-07-22 17:12:37 · answer #6 · answered by Anonymous · 0⤊ 0⤋
A) E = .6 (200 - A)
B) E= .6 (200 - A)
.6 (200 - 22)
.6 (178)
E = 106.8 bpm
2006-07-22 15:48:04 · answer #7 · answered by teekshi33 4 · 0⤊ 0⤋
A) (200 - A) x 60% = E
B) (200 - 22) x 60% = (178) * 60% = 106.8 so E = 106.8
2006-07-22 15:47:55 · answer #8 · answered by asmul8ed 5 · 0⤊ 0⤋
A.) z=heart rate, y=age
z=200-y x 60%
B.)106.8
2006-07-22 16:41:22 · answer #9 · answered by Jo-Jo 2 · 0⤊ 0⤋
A) E=(200-A) * .60
B) E=(200-22) * .60
E=178 * .60
E=106.8
2006-07-22 16:45:03 · answer #10 · answered by Anonymous · 0⤊ 0⤋