2006-07-22 07:18:52 · 5 answers · asked by kittytalker 3 in Science & Mathematics ➔ Chemistry
This is an example of the amide forming reaction
RCOX + H2NR' --> R(C=O)(NH)R' + HX
If the group X is -OH, this reaction is not very effective at ordinary temperatures, but at higher temperatures it will work well. In your situation, R- and R'- are methyl groups, and you get
CH3COOH + H2NCH3 --> CH3CONHCH3 + H2O
The product is N-methylethanamide.
2006-07-22 11:25:07 · answer #1 · answered by dutch_prof 4 · 3⤊ 0⤋
StephenB is correct here.
If you don't heat the reaction, the energy barrier towards making the amine is too large, relative to that for the acid/base reaction. You'll get protonated methamine and deprotonated acetic acid.
If you heat it, though, then you'll get the amide.
Another option, if you don't like heat (or if the target molecule is heat sensitive), would be to react the acetic acid with thionyl chloride. That would generate an acid chloride, which is much more open to nucleophilic attack from that amine.
2006-07-23 00:38:48 · answer #2 · answered by niuchemist 6 · 0⤊ 0⤋
Depending on the conditions, your first product would probably be MeCO2- MeNH3+ (the salt). Heating this would probably then eliminate water to yield MeCONHMe (an amide) + H2O
2006-07-22 15:20:06 · answer #3 · answered by Stephan B 5 · 0⤊ 0⤋
CH3C(O)=NHCH3 + H2O
ELIMINATION OF A WATER MOLECULE TAKE PLACE
2006-07-22 14:33:13 · answer #4 · answered by brainyguy 2 · 0⤊ 0⤋
CH3CONHCH3 + H2O
2006-07-22 14:49:57 · answer #5 · answered by papa 2 · 0⤊ 0⤋