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Evaluate

(From 65 to 0) 1/(t +1)^1/3 dt

A) 765/4

B) 51/2

C) 24

D) 45/2

2006-07-22 07:00:42 · 2 answers · asked by its me a 1 in Science & Mathematics Mathematics

2 answers

No one is correct. The answer is 3(1-66^(2/3))/2 . It is a negative number. Maybe there are some mistakes in your question. All the answer to choose are positive number so the interval must be: from 0 to 65.

If your question were " form 0 to 63 " the correct answer is D

2006-07-22 14:45:37 · answer #1 · answered by vahucel 6 · 0 0

I don't see the 65 to 0 part myself...

But the derivative is just the Product Rule.

2006-07-22 12:08:56 · answer #2 · answered by merlin2530 2 · 0 0

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