what is the importance of hybridization in organic chemistry?

Answer 1

When we speak of s-, px-, py- and pz-orbitals, we classify the possible states of the electrons in terms of four basic orbitals that are easiest to work with in quantum theory.

However, electrons can occupy a mixture of these orbits. When dealing with symmetric situations, such as the four C-H bonds in methane, it is handier to use a different description.

In methane, the four electron pairs do not occupy specific s-, px-, py- and pz-orbitals. If that were the case, one bond would be chemically different than the three others. Instead, they all occupy similar "mixed" orbitals (25% s and 75% p each).

Describing the situation in terms of these "mixed" orbits is called hybridization. In the example of methane, it helps you realize that the four bonds are really similar and symmetric; something you would not know if you thought of them in terms of the non-hybridized s- and p-bonds.

Answer 2

Organic Chemistry Hybridization

Answer 3

Let's take methane as an example:
Before carbon bond with hydrogen, it must have the bonding pairs orbitals all have the same energy. so the s & p orbitals of level 2 compine to form sp3 (put this three up pls.). They look like a half p. Now the hydrogens neclie get inside the sp to make the bond.

So it is important to have the outer shell's orbitals all having the same level. Hybridazation makes that!

Answer 4

Hybridization of the bonds tells you what kind of bonds you can form, which also tells you bond angles (approximately). It's pretty important stuff to know.

Answer 5

hybridization is very essential n imp specially if u r a chemistry student u have to know them..I dreaded them when I didn know them but once I did it became all easy..hybridization tells us all abt the bonds n its reactivity..once u know how hybrid a bond is u can calculate its reactivity n its ability to make new bonds..