f(x) = 3x + 2, f =(a + 1)
A) 3a + 5
B) 3a + 3
C) a + 6
D) a + 5
2006-07-21 21:13:59 · 6 answers · asked by cherryblueish 2 in Science & Mathematics ➔ Mathematics
f(x) = 3x + 2,
I take it that you need to find,
f(a + 1)
which is,
f(a + 1) = 3(a + 1) + 2
= 3a + 3 + 2
= 3a + 5
So the answer is option (A)
2006-07-21 21:18:17 · answer #1 · answered by ideaquest 7 · 0⤊ 0⤋
The problem isn't quite written right, first. It should be:
f(x)=3x+2, find f(a+1)
All you do is substitute a+1 where you see x.
3(a+1)+2
Then, you just solve use algebra. In this case, you use the distributive property (ok, I may have the name wrong; it's been a while), which means that when you have a number multiplied by something in parenthesis, it's the same as multiplying it by everything in the parenthesis.
So,
3(a+1)+2 =
3a + (3*1) + 2
Of course, three times one is three, so:
3a + 3 + 2
Then just add:
3a + 5
Good luck in the future!
2006-07-21 21:19:28 · answer #2 · answered by Daniel S 5 · 0⤊ 0⤋
3a + 5 is the answer
2006-07-21 21:19:15 · answer #3 · answered by Critical Mass 4 · 0⤊ 0⤋
it is 3a+5
2006-07-21 21:49:05 · answer #4 · answered by selvi_mks89 3 · 0⤊ 0⤋
If you were smart enough to do your own homework, you might be smart enough to ask the question coherently. You failed to state what the possible outcomes (A-D) were supposed to represent.
2006-07-21 21:19:04 · answer #5 · answered by Bush Whacker 3 · 0⤊ 0⤋
E) do your own homework
2006-07-21 21:15:35 · answer #6 · answered by tony pepperoni 3 · 0⤊ 0⤋