bus traveled from townx to towny with speed of 75km/h.car traveled from x 2 y 48 min later.wad time they meet?

Question

if u cant understand da qn above...here it is in da original text. A tour bus started its journey from town X to town Y. A car started its journey from the same place 48 min later. At what time would the car and the bus meet during the journey?

the speed of the car is 95km/h.

Answer 1

I couldn't understand the question at first because of your apprehensible typing, not because of the mathmatics.

How fast is the car going?

edit

I think 3 hrs? At 48 minutes, the bus would be 60 miles away. Every hour, the car would gain 20 miles.

Answer 2

Let the car’s time be x, so the bus travelled for x + 48 minutes

Distance bus travelled in 48 minutes = 48/60 * 75 = 60Kms

So they will meet when they have travelled the same distance.

X*75 + 60=x*95

95x –75x = 60

20x =60

x=3

So 3 hours after the car left they will meet or 3 hours 48 after the bus left they will meet.

In your jargon: dey wud meat tree hours after da car left

Proof

Distance car travelled = 3 hours * 95 = 285

Distance bus travelled = 3 hours * 75 + 60 = 285

Answer 3

in 48 min the bus would have covered 60 km
the relative vel of the car w.r.t. the bus 95-75=20 kph
this 60 km will be close in 60/20=3 hours
so they will meet 3 hrs after the car leaves or 3hrs 48 min after the bus leaves

Answer 4

didn't they give u the speed of the car???

Answer 5

What is the speed of the car ??????????????