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I mean except the two second diagonals by the side of the Pascal's Triangle which consists of consecutive numbers.

If yes, can you say what it is and where does it appear in the Pascals' Triangle?

If no, can you pls proove it?

2006-07-21 20:06:39 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

4 is not a prime!! its 2x2!!

2006-07-21 20:17:21 · update #1

3 answers

The numbers in Pascal's Triangle are the binomial coefficients. They are all of the form nCk = n!/k!(n-k)!
nC0 = nCn = 1
nC1 = nC(n-1) = n

For other values of k, the terms in nCk cannot cancel to leave a single prime factor.
Why?
For 1 < k, n < nCk, if nCk is prime it has to be a prime larger than n, but it is the product of terms that are all less than n, so that can't be the case.

2006-07-22 07:57:37 · answer #1 · answered by rt11guru 6 · 4 0

No, there are not any.

Here is why.

If it is even, it is not prime.

If it is odd, then it is divisible by an element within the prime factorization of the value next to it nearest its 1 diagonal.

So the only prime numbers occur on the 2nd diagonal.

Q.E.D.

2006-07-22 03:12:28 · answer #2 · answered by palffy68 3 · 0 0

thuier are millions.eg:1,3,5,7............

2006-07-22 05:26:55 · answer #3 · answered by dpala 2 · 0 0

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