2006-07-21 19:25:51 · 23 answers · asked by sweet2dabelly 1 in Science & Mathematics ➔ Mathematics
2x / 5 - x / 3 = 5
6x / 15 - 5x / 15 = 5
x / 15 = 5
x = 75
2006-07-21 19:41:25 · answer #1 · answered by jimbob 6 · 1⤊ 1⤋
Since you have 2 fractions with different denominators, the KEY is to first convert both fractions to a common denominator, and then do your rearranging to solve for X.
The quickest way to get a common denominator is to multiply the two current denominators together, which would give you 15 in this case. Now, you'd take each fraction 2X/5 and X/3, and convert each of these into 15ths.
Next, you'd group the X's all together. So if you ended up with 5X - 3X, you'd really have only 2X. Since this would be divided by the new denominator of 15, you'd need to isolate the X's by multiplying both sides by 15.
Then you'd divide both sides by whatever X is being multiplied to, which would give you the value of X.
2006-07-22 19:23:43 · answer #2 · answered by msoexpert 6 · 0⤊ 0⤋
2x/5 - x/3=5?
X(2/5-1/3)=5
X.1/15=5
X=75
2006-07-22 02:38:34 · answer #3 · answered by Rim 6 · 0⤊ 0⤋
6x/15 - 5x/15 = 5 so then 6x - 5x = 75 or x = 75
150/5 - 75/3 = 5 or 30 - 25 = 5
2006-07-22 02:31:30 · answer #4 · answered by asmul8ed 5 · 0⤊ 0⤋
first find the L.C.M of 3 and 5 and its 15.So the equation becomes x/15=5 which gives the answer as 75.
2006-07-22 02:30:11 · answer #5 · answered by hopy 1 · 0⤊ 0⤋
2x/5-x/3=5
or, 6x-5x/15=5(sine lcm of 3 and 5 is 15)
or, x/15=5
x=75
2006-07-22 07:17:34 · answer #6 · answered by gajendra k 2 · 0⤊ 0⤋
x = 75
2006-07-22 02:54:47 · answer #7 · answered by just me 4 · 0⤊ 0⤋
x = 75
2006-07-22 02:30:12 · answer #8 · answered by ? 3 · 0⤊ 0⤋
x=75
2006-07-22 02:43:48 · answer #9 · answered by Anonymous · 0⤊ 0⤋
2x/5 - x/3=5 multiply through by 5x3=15 to get rid of divisors
6x-5x=75
x=75
2006-07-22 02:32:06 · answer #10 · answered by helixburger 6 · 0⤊ 0⤋
x=75
2006-07-22 02:29:06 · answer #11 · answered by srinu710 4 · 0⤊ 0⤋