2006-07-21 19:23:53 · 13 answers · asked by sweet2dabelly 1 in Science & Mathematics ➔ Mathematics
3p^2 + 5pq - 2q^2
2006-07-21 19:28:28 · answer #1 · answered by *AstrosChick* 5 · 0⤊ 0⤋
3p^2 + 5pq - 2q^2
2006-07-21 19:28:30 · answer #2 · answered by ? 3 · 0⤊ 0⤋
= 3p^2 - pq + 6pq - 2q^2 (3p square - pq + 6pq - 2qsquare)
= 3p^2 + 5pq - 2q^2 (3p square + 5pq - 2q square)
2006-07-21 19:52:56 · answer #3 · answered by Rabindra 3 · 0⤊ 0⤋
3p^2+5pq-2q^2
2006-07-21 19:41:32 · answer #4 · answered by hiteshi n 1 · 0⤊ 0⤋
Front outside inside last
FOIL
2006-07-21 19:27:48 · answer #5 · answered by Erica T 4 · 0⤊ 0⤋
(p+2q)(3p-q)
p.3p+6pq-pq-2q.q
3pp+5pq-2qq
2006-07-21 20:08:28 · answer #6 · answered by Rim 6 · 0⤊ 0⤋
set it equal to 0, then go from there.
2006-07-21 19:28:18 · answer #7 · answered by cyanne2ak 7 · 0⤊ 0⤋
Cheeseburgers are yummy.
2006-07-21 19:28:22 · answer #8 · answered by Drizzle 2 · 0⤊ 0⤋
3psquare-pq+6pq-2qsquare
=3psquare+5pq-2qsquare
2006-07-21 19:26:16 · answer #9 · answered by srinu710 4 · 0⤊ 0⤋
4p+q
2006-07-21 19:27:14 · answer #10 · answered by Anonymous · 0⤊ 0⤋