Find the slope of any line perpendicular to the line through points (0, 5) and(3, 4).?

Answer 1

the slope of a line perpendicular to the given line joining x1,y1 and x2,y2 is -[(x1-x2)/(y1-y2)] =>x2-x1/y1-y2 =>3-0/5-4=3

Answer 2

a million. (y2 – y1)/(x2 – x1) = (-9 - 4)/(-5 - -6) = -thirteen/ a million = -thirteen 2. (y2 – y1)/(x2 – x1) = (2 - -7)/(6 - 6) = 9/0 = undefined 3. (y2 – y1)/(x2 – x1) = (a million - -3)/(-2 - 7) = 4/-9 = -4/9 4. y = 8 y = 0x + 8 slope = 0.5. 2x - 3y = sixteen 2x -sixteen = 3y 3y = 2x - sixteen y = 2/3 x - sixteen/3 slope = 2/3 6.a) 3x - 4y = 7 3x - 7 = 4y 4y = 3x - 7 y = 3/4 x - 7/4 and 8x + 6y = 7 6y = -8x + 7 y = -8/6 x + 7/6 y = -4/3 x + 7/6 because of the fact the slopes are 3/4 and -4/3 (they're damaging inverses of the different) the strains are perpendicular. b) y = 4x - 3 and 16x + 4y = 7 4y = -16x + 7 y = -4x + 7 those strains are neither parallel or perpendicular because of the fact to be parallel the slopes could desire to be equivalent or to be perpendicular they could desire to be damaging inverses. they're neither. 7. y = mx + b b is the y-intercept, that's given because of the fact the element. y = 0x + a million y = a million 8. a) y - y1 = m(x - x1) y - 5 = -3(x - 5) y - 5 = -3x + 15 y = -3x + 15 + 5 y = -3x + 20 b) (0, 6); m = 3/2 y = mx + b (comparable as 7) y = 3/2 x + 6 9. First locate slope. m = (y2 - y1)/(x2 - x1) = (-10 - -8)/(-6 - -6) = -2/0

Answer 3

To get a perpendicular slope you take the negative reciprocal of the given slope. Your points give a slope of -1/3. The slope of a perpendicular line would be 3/1.

Answer 4

well..slope is rise over run and perpendicular lines are lines that make a 90 degree angle. would it be...1/-3?

Answer 5

-1