2 is an exponent. it is not a variable.
a = b
a² = ab . . . . . . . . . . . . . . . . . .a² = aa = ab, since a = b
a² - b² = ab - b² . . . . . . . . . . .subtract b² from both sides
(a - b)(a + b) = b(a - b) . . . . .factor a² - b² and ab - b²
a + b = b . . . . . . . . . . . . . . . . .cancel (a - b) from both sides
incidentally, a =0, b = 0
i do feel as tho answering this was a little of a waste of time since this is not a real equation and that the reason you asked this question was something like resentment.
2006-07-21 13:06:11
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answer #1
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answered by warm soapy water 5
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2
2006-07-21 18:05:29
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answer #2
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answered by mityaj 3
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When you defined that a=b you disproved yourself because
(a-b)=0 so now you have 0*(a+b)=b*0 so the equation equals 0=0
Your not going to disprove alebgra so just give up.
2006-07-21 18:24:23
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answer #3
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answered by DoctaB01 2
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2 = 2
2 = 2 + na
2 = 2 - na
2 = 2 + nb
2 = 2 - nb
2 = 2 + nab
2 = 2 - nab
2 = 2 + n(a - b)
2 = 2 + n(a + b)
2 = 2 - n(a + b)
2 = 2 - n(a - b)
2006-07-21 18:42:13
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answer #4
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answered by Steve H 2
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2 = 1, but you made a mistake at step #4 where you divided by (a-b). You are dividing by zero at this step which is incorrect leading to a fallacious answer.
2006-07-21 18:12:11
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answer #5
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answered by Puzzling 7
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if a=b
then a2=b2
then a2-b2=0 ;o)
so
0 = a2-b2=ab-b2
0=b(a-b)
gives a=0 and b=0 my man..!
2006-07-21 19:04:05
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answer #6
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answered by ws 2
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2=2 but a+b doesn't = b it equals 2b because a=b so it's b+b=2b.
2006-07-21 18:17:40
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answer #7
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answered by agfreak90 4
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uh 0 duh
2006-07-21 19:02:12
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answer #8
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answered by 1234567 2
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