No. The general fromula is
E^2=m^2c^4 +p^2c^2.
For photons, m=0 and we get E=pc.
At an event horizon, the spacetime geometry is such that light can't escape. The light will experience a red-shift due exchange with potential energy in the gravitational field ifit is going outward. This red-shift corresponds to a loss of energy (and hence momentum).
2006-07-21 06:02:49
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answer #1
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answered by mathematician 7
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In the accepted theory of physics, c is constant, so it never becomes zero.
In fact, the event horizon is defined as the events accessible for a photon (or any particle) that would travel with speed c or less.
The mass of a photon is zero. It has to be: particles with non-zero mass cannot travel at the velocity of light.
2006-07-21 06:03:24
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answer #2
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answered by dutch_prof 4
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A photon is massless, and its speed can never be zero, it is always traveling at the same speed, at the event horizon the spacetime it moves through is distorted so that time passes at the rate of zero so the light is frozen in time, not slowed.
2006-07-21 06:18:05
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answer #3
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answered by Anonymous
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shifting on the speed of light purely the article will develop into endless in mass which have some mass, even as talking about PHOTON first you should keep in mind that, does PHOTON have mass? No! PHOTON would not have mass, so how can a massless merchandise be endless? I hop this may help you...
2016-11-25 00:18:29
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answer #4
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answered by ng 4
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Photons have no mass--plenty of confusion on this site about relativistic mass. At an event horizon, space-time is warped to the point that despite the fact that a photon is traveling in a straight line at the speed of light, it can't escape. From a different frame of reference you could perceive that the track that the photon is following is curved in on itself, but from the photon's frame of reference, it's still traveling in a straight line.
2006-07-21 06:27:34
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answer #5
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answered by Pepper 4
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