can any one post me an programe for reverse of digits of any number.?

Question

a c++ programe

Answer 1

U havnt mentioned any language?
1.Check if the num.has more than 1 digit . If No, -re-enter
2. Say the num is A
3.divide A by 10. Store Remainder in B. & the Result R=R*10 + B
4. If A isnt 0-zero continue step 3.
5. Final ans is R

Answer 2

This method lacks eleganance but will work.

1- Convert the number to a string.
2- Parse the string one char at a time to build a new string in the reverse order.
3- Convert the string back to a number.

Answer 3

you may have to change my syntax, i haven't done this in a while
instead of 732, you can have any number you want, but keep the other two equal to 0

int orig = 732;
int rev = 0;
int temp = 0;
do
{
temp = {mod 10 of}(orig);
rev = rev*10 + temp;
orig = orig/10;
} while (orig>0);

this will work because i made them all integers
review the mod function if you need to