2006-07-20 23:17:29 · 8 answers · asked by Muhammad Nadeem Haidere 1 in Science & Mathematics ➔ Mathematics
dy=(sin(x+y)+cos(x+y))dx
integrate on both sides,
y=-cos(x+y)+sin(x+y)
2006-07-21 02:36:00 · answer #1 · answered by jai 2 · 3⤊ 1⤋
Let V = x+y
dV / dx = 1 + dy / dx
Qn. is dV / dx -1 = sin V + cos V
Now solve
2006-07-20 23:24:36 · answer #2 · answered by shyam 2 · 0⤊ 0⤋
Let v=x+y,
dv/dx =1+dy/dx'
so,
dv/dx =sin v +cos V +1
now solve it in normal way.
After solving apply x and y instead of v.
2006-07-21 00:48:58 · answer #3 · answered by Shehan 4 · 0⤊ 0⤋
The answer from jai above mine is the easiest way tho solve that problem.
2006-07-21 03:15:58 · answer #4 · answered by metalmurf 2 · 0⤊ 0⤋
isn't d/dx (y cosx) = cosx y' - sinx y; extremely of cosx y' + sinx y? cosx y' + sinx y = sinx cosx y' + sinx/cosx y = sinx cosx/cosx y' + tanx y = sinx integrating ingredient: I(x) = e^(?tanx dx) I(x) = e^(ln?secx?) I(x) = secx secx y' + secx tanx y = secx sinx secx y' + secx tanx y = tanx d/dx (y secx) = tanx y secx = ?tanx dx y secx = ln?secx? + C y = cosx ln?secx?+ C cosx
2016-12-10 11:31:41 · answer #5 · answered by rickert 4 · 0⤊ 0⤋
on integrating it becomes
-cos(x+y)+sin(x+y)
2006-07-20 23:38:30 · answer #6 · answered by butterfly_skt 1 · 0⤊ 0⤋
do you mean solve or integrate?
2006-07-20 23:21:01 · answer #7 · answered by blind_chameleon 5 · 0⤊ 0⤋
How do you like my Avatar?
2006-07-20 23:21:52 · answer #8 · answered by AlbertaGuy 5 · 0⤊ 0⤋