Solve the following set of equation by elimination method3x-4y-z=1x+2y-3z= -24x+3y-2z= -1?

Question

Solve the following set of equation by elimination method

3x-4y-z=1
x+2y-3z= -2
4x+3y-2z= -1

Answer 1

x = 13/60
y = -7/30 = -14/60
z = 7/12 = 35/60

x = 13/60, y = -14/60, z = 35/60

Answer 2

first elemination
3x - 4y - z = 1 |x1| 3x - 4y - z = 1
x + 2y -3z = -2 |x3| 3x + 6y -9z = -6 (-)
--> -10y + 8z = 7 ...(1)

second elemination
4x + 3y -2z = -1 |x1| 4x + 3y - 2z = -1
x + 2y -3z = -2 |x4| 4x + 8y -12z = -8 (-)
--> -5y + 10z = 7

third elemination
-10y + 8z = 7 |x1| -10y + 8z = 7
-5y + 10z = 7 |x2| -10y + 20z = 14 (-)
--> -12z = -7, and z = 7/12

put z into -5y + 10z = 7 and we get y = -7/30
put y and z into equation x + 2y -3z = -2 and we get x = 13/60

writing all the result
x = 13/60, y = 7/30, and z = 7/12

Answer 3

first elemination
3x - 4y - z = 1 |x1| 3x - 4y - z = 1
x + 2y -3z = -2 |x3| 3x + 6y -9z = -6 (-)
--> -10y + 8z = 7 ...(1)

second elemination
4x + 3y -2z = -1 |x1| 4x + 3y - 2z = -1
x + 2y -3z = -2 |x4| 4x + 8y -12z = -8 (-)
--> -5y + 10z = 7

third elemination
-10y + 8z = 7 |x1| -10y + 8z = 7
-5y + 10z = 7 |x2| -10y + 20z = 14 (-)
--> -12z = -7, and z = 7/12

put z into -5y + 10z = 7 and we get y = -7/30
put y and z into equation x + 2y -3z = -2 and we get x = 13/60

writing all the result
x = 13/60, y = 7/30, and z = 7/1

Answer 4

x=-29/38

y=-7/38

z=-96/38

*i didn't check my answers so i could be wrong*

Answer 5

tumbleweed tumbles past in head*

Answer 6

3x-4y-z=1 ........................................(1)
x+2y-3z=-2..................................................(2)
4x+3y-2z=-1................................................(3)
(1)*2-(3) gives
2x-11y=3.....................................................(4)
(1)*3-(2) gives
8x-14y=5......................................................(5)
(4)*4-(5)
y=-7/30
substituting
x=13/60
sub x and y z=7/12
sothe soln.set{13/60,-7/30,7/12}