1 family has 10 babies. probabality born boy=born girl. Probability for number of boys= from 3 to 7?

Question

a.0,689 b .0,76 c0,89 d.0,692

Answer 1

c 0,89

Girls outnumber Boys 10 to 1 already.

Answer 2

This problem involves the binomial equation. If p is the "success" probability (boys), q = 1 - p the "failure" probability (girls), n the total number of experiments (babies), then the probability of x "successes" (boys) equals

p(x) = (n C x) . p^x . q^(n-x)

where (n C x) is the binomial coefficient.

In this problem p = q = 0.5 and n = 10, and the formula simplifies as

p(x) = (10 C x) . (0.5)^10 = (10 C x)/1024.

We calculate and add the probabilities for x = 3 through 7:

p(3) = (10 C 3)/1024 = 120/1024
p(4) = (10 C 4)/1024 = 210/1024
p(5) = (10 C 5)/1024 = 252/1024
p(6) = (10 C 6)/1024 = 210/1024
p(7) = (10 C 7)/1024 = 120/1024

total: 912/1024 = 0.890625, or ~ 89%

(answer c is correct)

Answer 3

a million. 1880: Mary Alice and Thomas Charles 2. 1890: Elizabeth Grace and William Edward 3. 1900: Lillian Rose and Joseph James 4. 1910: Evelyn Louise and Henry Robert 5. 1920: Margaret Marie and Richard Walter 6. 1930: Patricia Jean and David George 7. 1940: Judith Barbara and Michael Kenneth 8: 1950: Deborah Carol and Ronald Stephen 9. 1960: Pamela Cheryl and Donald Brian 10. 1970: Melissa Amy and Christopher Daniel 11. 1980: Heather Michelle and Andrew Nicholas 12. 1990: Lauren Samantha and John Matthew 13. 2000: Abigail Olivia and Zachary Jacob 14. 2009: Sophia Natalie and Benjamin Alexander I used in basic terms the right 20 names for each gender. - Amy

Answer 4

actually it is one half. practically though it might be one of your answers but scientifically it is one half.